1 centimetre=0.1 decimetre
therefore the answer is 2.5 decimetres.
4120_7 = 4•7³ + 1•7² + 2•7¹ + 0•7⁰
4120_7 = 4•343 + 1•49 + 2•7 + 0•1
4120_7 = 1372 + 49 + 14
4120_7 = 1435
In base 12, we use the digits 0-9 as well as A for 10 and B for 11. So
A3B_12 = 10•12² + 3•12¹ + 11•12⁰
A3B_12 = 10•144 + 3•12 + 11•1
A3B_12 = 1440 + 36 + 11
A3B_12 = 1487
In base 36, we assign values between 10 and 35 to the letters A-Z, so that
WXYZ_36 = 32•36³ + 33•36² + 34•36¹ + 35•36⁰
WXYZ_36 = 32•46656 + 33•1296 + 34•36 + 35•1
WXYZ_36 = 1492992 + 42768 + 1224 + 35
WXYZ_36 = 1537019
Answer:
37 mph
Step-by-step explanation:
Sum of forces on the car in the y direction:
∑F = ma
N − mg = 0
N = mg
Sum of forces on the car in the x direction:
∑F = ma
-Nμ = ma
-mgμ = ma
-gμ = a
Given μ = 0.75 and g = 32 ft/s²:
a = -(32 ft/s²) (0.75)
a = -24 ft/s²
Use kinematics to find the initial velocity.
v² = v₀² + 2aΔx
(0 ft/s)² = v₀² + 2 (-24 ft/s²) (60 ft)
v₀ ≈ 53.7 ft/s
v₀ ≈ 37 mph
Step-by-step explanation:
There are ₉C₂ ways to choose 2 students from 9.
There are ₁₅C₂ ways to choose 2 teachers from 15.
There are ₂₄C₄ ways to choose 4 people from 24.
Therefore, the probability is:
P = ₉C₂ ₁₅C₂ / ₂₄C₄
P = 36 × 105 / 10626
P ≈ 0.356
