Answer: X = 3t, Y =2 - t, Z =2
Step-by-step explanation: the plane
x + y + z =4has normal vector
M =<1,1,1> and the line
x = 1 + t, y = 2 − t, z = 2t has direction
v =<1, −1, 2>. So the vector
A= n × v
=<1, 1, 1> × <1, −1, 2>
=<2−(−1),1−2,−1−1>
=<3,−1,−2>
Answer:
3y = -2x -7
Step-by-step explanation:
The equation of the line;
y =
x + 8
Unknown:
Equation of the line passing through (4, -5);
Solution:
To solve this problem;
the equation of a line is given as;
y = mx + c
where x and y are the coordinate
m is the slope
c is the intercept
To solve this problem,
The slope
if the same as that of the new line since they are parallel;
Equation of the new line;
x = 4 and y = -5
-5 =
x 4 + c
-5 =
+ c
c = -5 + 
c = 
So, the equation of the line is;
y =
x - 
or ;
3y = -2x -7
Answer:
g(x)=6 and f(x)=3 these are your answers for this equation
As x heads off to negative infinity (towards the left side), the curve slowly approaches the horizontal line y = 1. It will never actually touch or cross this horizontal line. It simply gets closer and closer. Think of it as an electric fence of sorts.
Therefore the horizontal asymptote is y = 1