Answer:
Yes,
Step-by-step explanation:
because two sides are shown equal to each other, a and b. Also two angles are equal to each other, x and y. Once you know two angles or two sides are equal so is the third side.
Another way is SAS (side angle side). There is side a, angle y, and side b. These are shown on both triangles.
Therefore, we can conclude these two triangles are congruent.
(1)Draw the "y" line . It goes up and down.
<span>Make sure to mark the centimeters or quarter inches with little nobs. </span>
<span>Start at -20 and go to 10 </span>
<span>(2)Draw the "x" line. it goes side to side. </span>
<span>place the x line at the zero point of the y line. I'm sure you will see your paper looks like the letter "t". Perfectly at a right angle. you could use the corner of a book to square it. </span>
<span>Now for the maths 5x - 4y = -18. The most important symbol here is the "=" sign. </span>
<span>(3) rearrange the equation so that y is on one side of "=" and x is on the other side. </span>
<span>Remember if you add 10 to one side the of "=" , then for it to be equal, add 10 to the other. side also </span>
<span>so add 4y to both sides. add 18 to both sides . divide the whole of each side by 4. </span>
<span>5x - 4y + 4y + 18 = -18 + 4y + 18 </span>
<span>1.25x + 4.5 = y </span>
<span>(4) now write down on a peace of scrap paper, x=1, y= 5.75, x=2 y= ___ , x=3 y= ___ </span>
<span>(5) remember BEDMAS, and put 1 in the place of x and calculate what y is . </span>
<span>(6) get your ruler , line up x = 1 (ruler is going up and down) and draw a spot on what y = . Get two rulers if you must. </span>
<span>(7) </span>
<span>hey presto, you got your three points on a graph.</span>
6 miles = 1in
9 miles = 1 1/2in
12 miles = 2in
and it goes on, hope this helps!
Answer:
5
Step-by-step explanation:
For an equation to be dimensionally correct the dimension of quantities on both sides of equation must be same.
Also, two physically quantities can only be added or subtracted only when their dimension are same.
here all option are dimensionally correct except the 5th option where
dimension of t= [T] whereas dimension of a/v is 
= T^{-1}
since, the dimension of quantities on either sides of equation are not the same the equation is dimensionally is incorrect.
