Y= mx+b (slope intercept form)
m= the slope (in this case 8)
b= the y-intercept (-3)
the answer: y=8x-3
For the given sentences, the algebraic expressions are:
a) N = 110*c - 300
b) N = 12*b
<h3>
How to get the algebraic expressions?</h3>
For the first statement:
A 3-digit number, where the tens digit is c, can be written as:
N = 100*a + 10*c + b
Then the hundreds digit is a, and here we know that is 3 less than the tens digit, then:
a = c - 3
The ones digit is b, here we know that it is 0, then b = 0.
Replacing that in our number we get:
N = 100*(c - 3) + 10*c = 110*c - 300
N = 110*c - 300
That is the algebraic expression.
b) A two-digit number can be written as:
N = b*10 + a
Where b is the tens digit and a is the ones digit.
Here we know that the units digit is twice as bit as the tens digit, then:
a = 2b
Replacing that we get:
N = b*10 + a = b*10 + 2b = 12*b
N = 12*b
That is the algebraic expression.
If you want to learn more about algebraic expressions:
brainly.com/question/4541471
#SPJ1
Answer:
218
Step-by-step explanation:
ATQ,
22%of total books = 48
Let the total no. of books in library be x.
22/100x=48
x=4800/22
X=218(approximately)
Answer: To confuzing
Step-by-step explanation:
I've answered your other question as well.
Step-by-step explanation:
Since the identity is true whether the angle x is measured in degrees, radians, gradians (indeed, anything else you care to concoct), I’ll omit the ‘degrees’ sign.
Using the binomial theorem, (a+b)3=a3+3a2b+3ab2+b3
⇒a3+b3=(a+b)3−3a2b−3ab2=(a+b)3−3(a+b)ab
Substituting a=sin2(x) and b=cos2(x), we have:
sin6(x)+cos6(x)=(sin2(x)+cos2(x))3−3(sin2(x)+cos2(x))sin2(x)cos2(x)
Using the trigonometric identity cos2(x)+sin2(x)=1, your expression simplifies to:
sin6(x)+cos6(x)=1−3sin2(x)cos2(x)
From the double angle formula for the sine function, sin(2x)=2sin(x)cos(x)⇒sin(x)cos(x)=0.5sin(2x)
Meaning the expression can be rewritten as:
sin6(x)+cos6(x)=1−0.75sin2(2x)=1−34sin2(2x)
