Answer:
60.0735651 degrees
Step-by-step explanation:
So the hypotenuse is 50 and the vertical leg is 13
For the angle, you need to find the sine (opposite and hypotenuse)
sin(x) = 13/50
x = asin(13/50)
x = 60.0735651
Answer:
The equation of line passing through points (1 , 0) is x - 5 y - 1 = 0
Step-by-step explanation:
Given equation of line as
x + 5 y = 30
Now, equation of line in standard form is y = m x + c
where m is the slope
So, x + 5 y = 30
Or, 5 y = - x + 30
Or, y = - x + 6
So, Slope of this line m = -
Again , let the slope of other line passing through point (1 , 0) is M
And Both lines are perpendicular , So , products of line = - 1
i.e m × M = - 1
Or, M = -
Or, M = - 1 × - =
So, equation of line with slope M and points (1, 0) is
y - = M × (x - )
Or, y - ( 0 ) = × ( x - 1 )
Or, y = x - × 1
Or, y = x -
or, y + = x
Or, 5×y + 1 = x
∴ 5 y + 1 = x
I.e x - 5 y - 1 = 0
Hence The equation of line passing through points (1 , 0) is x - 5 y - 1 = 0 Answer
Answer:
Here,
(cosθ + sinθ/sinθ) – (cosθ – sinθ/cosθ) = secθ cscθ
Now, Cross Multiplication
(cosθ + sinθ/sinθ) – (cosθ – sinθ/cosθ) = secθ cscθ
cosθ(cosθ + sinθ) – sinθ(cosθ – sinθ)/sinθ cosθ
cos²θ + sinθ cosθ – sinθ cosθ + sin²θ/sinθ cosθ
cos²θ + sin²θ/sinθ cosθ
Here, we know the identity
cos²θ + sin²θ = 1
So,
cos²θ + sin²θ/sinθ cosθ can be written as
1/sinθ cosθ
Here, we also know the identity
1/sinθ = cscθ
1/cosθ = secθ
1/sinθ cosθ can be written as
secθ cscθ
= L.H.S
Hence Proved!!
<u>-TheUnknownScientist</u><u> 72</u>
Area = 3.14(r^2)
Area = 3.14(4^2)
Area = 3.14(16)
Area = 50.2
The answer is C
Your answer will be 96 hope this helps :)