A. Which reduction should she use so the picture fills as much of the frame as possible, without being too large?
Find the scale factor to get rom 7 1/3 inches to 5 1/3 inches:
5 1/3 / 7 1/3 = 0.7272
Now rewrite the fraction as decimals:
2/3 = 0.667
¾ = 0.75
5/9 = 0.555
The closest scale that would still fit the frame would be 2/3 because it is under 0.727.
B. How much extra space is there in the frame when she uses the reduction from Part A?
Multiply the original size by the scale factor to use:
7 1/3 x 2/3 = 4 8/9
Now subtract the scaled size from the original size:
7 1/3 – 4 8/9 = 2 4/9 inches extra
C. If she had a machine that could reduce by any amount, so that she could make the reduced picture fit in the frame exactly, what fraction would the reduction be?
Convert the scale from part A to a fraction:
0.72 = 72/99 which reduces to 8/11
1/4b=-3
Solve for b
1/4b *4 = -3*4
b = -3 *4
b = -12
Answer: b = -12
First, subtract 2/3 from both sides and you get
Then multiply both sides by 6/5 and you get
Answer:
$9
Step-by-step explanation:
These are given:
Total = 22
Cost for shoes = 4
Total games played = 2
Cost per game (g)= ?
So,
22 = 4 + 2(g)
-4 -4
18 = 2g
divide by 2
9 = g
$9 per game
Oh no my parrot is missing
