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4 years ago

Does the numerator impact whether a fraction will have a finite or infinite decimal?

1 answer:

6 0

Answer:DECIDING IF A FRACTION IS A FINITE OR INFINITE REPEATING DECIMAL ... Need a short break? RATIONAL and IRRATIONAL NUMBERS. The rational numbers are numbers that can be written in the form ab a b , ... start by putting the fraction in simplest form;; then, factor the denominator into primes.

Step-by-step explanation:

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Which statements are true regarding quadrilateral ABCD? Check all that apply.

Leto [7]

Answer:

ABCD has four congruent angles.

Step-by-step explanation:

5 0

3 years ago

A young sumo wrestler decided to go on a special diet to gain weight rapidly. He gained weight at a constant rate.

Fittoniya [83]

The wrestler gained 5.20 kilograms per month.

Step-by-step explanation:

Let,

x be the weight gained every month.

y be the original weight before weight gain.

According to given statement;

0.5x+y=80.6 Eqn 1

2x+y=88.4 Eqn 2

3.5x+y=96.2 Eqn 3

Subtracting Eqn 1 from Eqn 2

$(2x+y)-(0.5x+y)=88.4-80.6\\2x+y-0.5x-y=7.8\\1.5x=7.8$

Dividing both sides by 1.5

$\frac{1.5x}{1.5}=\frac{7.8}{1.5}\\x=5.20$

The wrestler gained 5.20 kilograms per month.

Keywords: linear equation, subtraction

Learn more about linear equations at:

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3 0

3 years ago

Read 2 more answers

Use Stokes' Theorem to evaluate C F · dr where C is oriented counterclockwise as viewed from above. F(x, y, z) = 2yi + xzj + (x

Lady_Fox [76]

By Stokes' theorem, the line integral of $\vec F$ over $C$ is given by the surface integral of the curl of $\vec F$ over $S$ , where $S$ is the region of intersection of the plane $z=y+6$ and the cylinder $x^2+y^2=1$ with $S$ having positive/upward orientation.

Parameterize $S$ by

$\vec s(u,v)=u\cos v\,\vec\imath+u\sin v\,\vec\jmath+(u\sin v+6)\,\vec k$

with $0\le u\le1$ and $0\le v\le2\pi$ .

Take the normal vector to $S$ to be

$\vec s_u\times\vec s_v=-u\,\vec\jmath+u\,\vec k$

The curl of $\vec F$ is

$\nabla\times\vec F(x,y,z)=(1-x)\,\vec\imath-\vec\jmath+(z-2)\,\vec k$

Then the line integral is equivalent to

$\displaystyle\int_C\vec F\cdot\mathrm d\vec r=\iint_S(\nabla\times\vec F)\cdot\mathrm d\vec S$

$=\displaystyle\int_0^{2\pi}\int_0^1\bigg((1-u\cos v)\,\vec\imath-\vec\jmath+(u\sin v+4)\,\vec k\bigg)\cdot\bigg(-u\,\vec\jmath+u\,\vec k\bigg)\,\mathrm du\,\mathrm dv$