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2 years ago

What two numbers add to 6 and multiply to 58

Mathematics

1 answer:

Korvikt [17]2 years ago

5 0

The two numbers which add to 6 and multiply to 58 are; 3+7i and 3-7i

<h3>Simultaneous equations;</h3>

According to the question;

let the two numbers be; x and y.

Hence;

x+ y = 6
xy = 58

x = 6-y which can the be be substituted into equation (ii) so that we have;

(6-y)y = 58

6y -y² = 58

y² - 6y +58 = 0

By solving quadratically; we have;

y = 3 + 7i Or y = 3-7i

x = 3 - 7i Or x = 3+7i

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Use a table of signs to solve the inequality

bulgar [2K]

The interval of the provided inequality expression is -5/9 to the infinity [(-5/9),∞) using the table of signs to solve the inequality.

<h3>What is the inequality equation?</h3>

Inequality equation is the equation in which the two expressions are compared with greater than, less than or other inequality signs.

The inequality given in the problem is,

$4x + \dfrac{5}{9} - 3x \geq 0$

Simplify the equation first by adding the same terms,

$4x + \dfrac{5}{9} - 3x \geq 0\\4x - 3x+ \dfrac{5}{9} \geq 0\\x+ \dfrac{5}{9} \geq 0\\x\geq-\dfrac{5}{9}$

Now in this case, if the value x is ranges from -5/9 to infinity.

Thus, the interval of the provided inequality expression is -5/9 to the infinity [(-5/9),∞) using the table of signs to solve the inequality.

Learn more about the inequality equation here:

brainly.com/question/17724536

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