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3 years ago

Solve the system using elimination: -3x - 3y = 12 -9x + 3y = -24The answer is not (-1,-3)

Mathematics

1 answer:

FinnZ [79.3K]3 years ago

5 0

Answer:

{x = 1, y = -5

Step-by-step explanation:

Solve the following system:

{-3 x - 3 y = 12 | (equation 1)

{3 y - 9 x = -24 | (equation 2)

Swap equation 1 with equation 2:

{-(9 x) + 3 y = -24 | (equation 1)

{-(3 x) - 3 y = 12 | (equation 2)

Subtract 1/3 × (equation 1) from equation 2:

{-(9 x) + 3 y = -24 | (equation 1)

0 x - 4 y = 20 | (equation 2)

Divide equation 1 by 3:

{-(3 x) + y = -8 | (equation 1)

{0 x - 4 y = 20 | (equation 2)

Divide equation 2 by 4:

{-(3 x) + y = -8 | (equation 1)

{0 x - y = 5 | (equation 2)

Multiply equation 2 by -1:

{-(3 x) + y = -8 | (equation 1)

{0 x+y = -5 | (equation 2)

Subtract equation 2 from equation 1:

{-(3 x)+0 y = -3 | (equation 1)

{0 x+y = -5 | (equation 2)

Divide equation 1 by -3:

{x+0 y = 1 | (equation 1)

{0 x+y = -5 | (equation 2)

Collect results:

Answer: {x = 1 , y = -5

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2 years ago

A company performs linear regressions to compare data sets for two similar

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2 years ago

Estimate the solution to the system of equations. You can use the interactive graph below to find the solution.−3x+3y=9 2x−7y=−1

hjlf

Answer:

(x, y) = (-1.4, 1.6)

Step-by-step explanation:

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3 years ago

Q1W7 Learning Task 1 (Introduction)

Tatiana [17]

Answer:

Column A Column B

1. x² + 6x + 8 x-3,x+2

2. x³ - 7x + 6 x+1, x+2, x+3

3. x³ - 2x² - 5x + 6 x-1, x+2, x-3

Step-by-step explanation:

Column A Column B

1. x² + 6x + 8 x-3,x+2

2. x³ - 7x + 6 x+1, x+2, x+3

3. x³ - 2x² - 5x + 6 x-1, x+2, x-3

Using Factor theorem we put values of x = ±1,±2,±3 in each of the polynomials unless we get a zero.

1. x² + 6x + 8

= 1+6(1) +8= 15

1. x² + 6x + 8

4+ 12+8 = 24

1. x² + 6x + 8

(-1)² + 6(-1)+ 8

= 1-6+8= 3

1. x² + 6x + 8

(-2)² + 6(-2)+ 8

= 4-12+8= 0

1. x² + 6x + 8

(3)²+ 6(3) +8

= 9+18+8 ≠ 0

1. x² + 6x + 8

(-3)²+ 6(-3) +8

= 9-18+8 =-1

For this polynomial we have x+2= 0 or x=-2, x-3= 0 , x=3

2. x³ - 7x + 6

1-7+6= 0

2. x³ - 7x + 6

(-1)³-7(-1) +6

= 13-1≠0

2. x³ - 7x + 6

(2)³-7(2) +6

= 8-14+6= 0

2. x³ - 7x + 6

(-2)³-7(-2) +6

= -8 +14+6

2. x³ - 7x + 6

(-3)³-7(-3) +6

= -27+21+6 = 0

For this polynomial we have x+1= 0 , x+2 = 0 and x+3= 0, or x=-1,-2,-3

3. x³ - 2x² - 5x + 6

(1)³-2(1)²-5(1)+6

= 0

3. x³ - 2x² - 5x + 6

(-1)³-2(-1)²-5(-1)+6

= -1 -2 +5+6

3. x³ - 2x² - 5x + 6

(2)³-2(2)²-5(2)+6

= 8-8-10+6

=-4

3. x³ - 2x² - 5x + 6

(-2)³-2(-2)²-5(-2)+6

= -8-8+10+6

3. x³ - 2x² - 5x + 6

(3)³-2(3)²-5(3)+6

= 27-18-15+6

3. x³ - 2x² - 5x + 6

(-3)³-2(-3)²-5(-3)+6

= -27-18+15+6

=-14

For this polynomial we have x-1= 0 ,x+2=0, x-3= 0or x=1,-2,3

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3 years ago

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3 years ago

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