I assume you're asked to solve
4 cos²(<em>x</em>) - 7 cos(<em>x</em>) + 3 = 0
Factor the left side:
(4 cos(<em>x</em>) - 3) (cos(<em>x</em>) - 1) = 0
Then either
4 cos(<em>x</em>) - 3 = 0 <u>or</u> cos(<em>x</em>) - 1 = 0
cos(<em>x</em>) = 3/4 <u>or</u> cos(<em>x</em>) = 1
From the first case, we get
<em>x</em> = cos⁻¹(3/4) + 2<em>nπ</em> <u>or</u> <em>x</em> = -cos⁻¹(3/4) + 2<em>nπ</em>
and from the second,
<em>x</em> = <em>nπ</em>
where <em>n</em> is any integer.
The roots of the given polynomials exist 
, and 
.
<h3>What is the formula of the quadratic equation?</h3>
For a quadratic equation of the form 
the solutions are
Therefore by using the formula we have
Let, a = 1, b = -16 and c = 54
Substitute the values in the above equation, and we get
simplifying the equation, we get
Therefore, the roots of the given polynomials are , and
.
To learn more about quadratic equations refer to:
brainly.com/question/1214333
#SPJ4
Answer:
25*0.92= 23 so she answered 23 question from 25 questions
Step-by-step explanation:
<em>For your question the answer is B.</em>
<em> Hope this helps:)</em>
