I agree with this person that will be a good use
[1]
A1 = (h (a + b)) / 2
A1 = (21 (17 + 32)) / 2
A1 = (21 x 49) / 2
A1 = 1,029 / 2
A1 = 514.5 mm²
[2]
A2 = (b x h) / 2
A2 = (11 x 9) / 2
A2 = 99 / 2
A2 = 49.5 mm²
[3]
The area of the shaded region =
A1 - A2 =
514.5 mm² - 49.5 mm² =
465 mm²
The answer is 465 mm².
Answer:
Step-by-step explanation:
Use Quadratic Formula to solve Real Life Quadratic Equation Problem.
Kaylani is going to make a blanket by sewing a 4-foot long piece of ribbon along the diagonal of a piece of rectangular fabric. She wants the length of the blanket to be 18 inches longer than the width. What is the approximate perimeter of the blanket? Round to the nearest inch.
<h2>
Answer with explanation:</h2>
Given : The proportion of New Zealanders consume five or more servings of soft drinks per week :![\hat{p}= 0.16](https://tex.z-dn.net/?f=%5Chat%7Bp%7D%3D%200.16)
a) The number of survey respondents reported that they consume five or more servings of soft drinks per week = 2006
b) Confidence interval for population proportion (p) :
![\hat{p}\pm z^*\sqrt{\dfrac{\hat{p}(1-\hat{p})}{n}}](https://tex.z-dn.net/?f=%5Chat%7Bp%7D%5Cpm%20z%5E%2A%5Csqrt%7B%5Cdfrac%7B%5Chat%7Bp%7D%281-%5Chat%7Bp%7D%29%7D%7Bn%7D%7D)
, where
= Sample proportion.
n= Sample size.
z* = Critical value.
For n= 2006 ,
and critical value for 95% confidence interval : z* = 1.96
Then , the required confidence interval will be :
![0.16\pm (1.96)\sqrt{\dfrac{ 0.16(1- 0.16)}{2006}}](https://tex.z-dn.net/?f=%200.16%5Cpm%20%281.96%29%5Csqrt%7B%5Cdfrac%7B%200.16%281-%200.16%29%7D%7B2006%7D%7D)
![0.16\pm (1.96)\sqrt{ 0.000066999002991}](https://tex.z-dn.net/?f=%200.16%5Cpm%20%281.96%29%5Csqrt%7B%090.000066999002991%7D)
![0.16\pm (1.96)(0.00818529186963)](https://tex.z-dn.net/?f=%200.16%5Cpm%20%281.96%29%280.00818529186963%29)
![0.16\pm 0.0160431720645](https://tex.z-dn.net/?f=%200.16%5Cpm%200.0160431720645)
![(0.16-0.0160431720645,\ 0.16+0.0160431720645)](https://tex.z-dn.net/?f=%280.16-0.0160431720645%2C%5C%200.16%2B0.0160431720645%29)
![(0.143956827935,\ 0.176043172064)\approx(0.144,\ 0.176)](https://tex.z-dn.net/?f=%280.143956827935%2C%5C%200.176043172064%29%5Capprox%280.144%2C%5C%200.176%29)
i.e. A 95% confidence interval for the proportion of New Zealanders who report that they consume five or more servings of soft drinks per week. = ![(0.144,\ 0.176)](https://tex.z-dn.net/?f=%280.144%2C%5C%200.176%29)
c) ![(0.144,\ 0.176)=(0.144\times100\%,\ 0.176\times100\%)](https://tex.z-dn.net/?f=%280.144%2C%5C%200.176%29%3D%280.144%5Ctimes100%5C%25%2C%5C%200.176%5Ctimes100%5C%25%29)
176\times100\%)[/tex]
d) The estimate might be biased because the survey is taken online that means offline New Zealanders are out of consideration.