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vova2212 [387]
3 years ago
9

I NEED ANSWER ASAP. BRAINLIEST​

Mathematics
1 answer:
vredina [299]3 years ago
7 0

Answer:

Wait I just realized, none of them are cubic? for a polynomial to be cubic it needs to be x^{3}

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A 128-ounce jug of milk costs $3.20, and a 64-ounce jug of milk costs $2.24. What is the difference in cost per ounce between th
klasskru [66]

Answer:

The 64 ounce jug of milk costs $0.010 more per ounce than the 128 ounce jug of milk/

Step-by-step explanation:

3.20/128=$0.025 per ounce jug of milk

2.24/64=$0.035 per ounce jug of milk

0.035 - 0.025 = .010

5 0
3 years ago
Please help me im having trouble but my teacher wont give out awnsers
Anastasy [175]

Answer: A

Step-by-step explanation: I just makes since to me. Suck that the teacher wont give you the answer.

7 0
3 years ago
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In the diagram, the radius of the outer circle is
JulijaS [17]

the value of x is 8 cm.

<u>Step-by-step explanation:</u>

Correct Question : In the diagram, the radius of the outer circle is 2x cm and the radius of the inside circle is 6 cm. The area of the shaded region is 220π cm2. What is the value of x? Enter your answer in the box.

We have ,

the area of a circle =  πr²

the outer circle area = \pi(2x)^2 =4\pi x^2

the inside circle area = \pi (6)^2= 36\pi

According to Question,

the outer circle area - the inside circle area = he shaded region

⇒ \pi (4x^2)-36\pi =220\pi

⇒ x^2-9 =55

⇒ x^2=64

⇒x =\sqrt{64}=8

Therefore , the value of x is 8 cm.

5 0
3 years ago
Can someone help me with this
Elanso [62]

Answer:

1,256 dm^2 and 400π dm^2

Step-by-step explanation:

The circumference is equal to 2pi times the radius. So 40pi=2pi times the radius so the radius is 20. The area of a circle is pi times the radius squared or 400pi and if using 3.14 for pi this would be 1,256 dm^2

6 0
2 years ago
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Find the value of ‘x’
Karolina [17]

Answer:

x=30

Step-by-step explanation:

the midpoint is half the top + the bottom so;

1/2 (27 + 33) = x

1/2 (60) = x

30 = x

MARK BRAINLIEST IF YOU GET IT RIGHT!!!!

5 0
3 years ago
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