Answer:
C. 
Step-by-step explanation:
Given: 
To find the domain of a logarithmic function, we need to take the argument, 8x, and set it greater to zero. This is because an argument of a logarithmic function cannot be zero or negative.


So since x is greater than zero, we have just found out our domain:
Interval Notation: (0, ∞)
Set Notation: {
}
Answer:
The answer is below.
Step-by-step explanation:
The options are not clear. I would solve a similar question.
A linear function is a function in the form:
y = mx + b; where y and x are variables, m is the slope and b is the y intercept.
From the options:
a) x(y - 5) = 2
xy - 5x = 2. Since the equation is not in the form of y = mx + b, hence it is not a linear function. It is a nonlinear function.
b) y - 2(x + 9) = 0
y - 2x - 18 = 0
y = 2x + 18. The equation is in the form of y = mx + b, hence it is a linear function.
c) 3y + 6(2 - x) = 5
3y + 12 - 6x = 5
3y = 6x - 7. The equation is in the form of y = mx + b, hence it is a linear function.
d) 2(y + x) = 0
2y + 2x = 0
2y = -2x. The equation is in the form of y = mx + b, hence it is a linear function.