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3 years ago

|8 - 22| I need help with this please :)

Mathematics

2 answers:

dem82 [27]3 years ago

6 0

Answer:

l8 - 22l = 14

Nuetrik [128]3 years ago

6 0

Answer: -203

Step-by-step explanation:

By explaining this answer, You first find out if this question can be answered with no negative numbers. As there is negative numbers in this problem you will have to subtract it the way you subtract a normal subtraction problem.

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Describe the sampling distribution of p(hat). Assume the size of the population is 30,000.

Naya [18.7K]

Answer:

a) $\mathbf{\mu_ \hat p = 0.6}$

b) $\mathbf{\sigma_p =0.01732}$

Step-by-step explanation:

Given that:

population mean $\mu$ = 30,000

sample size n = 800

population proportion p = 0.6

The mean of the the sampling distribution is equal to the population proportion.

$\mu_ \hat p = p$

$\mathbf{\mu_ \hat p = 0.6}$

The standard deviation of the sampling distribution can be estimated by using the formula:

$\sigma_p = \sqrt{\dfrac{p(1-p)}{n}}$

$\sigma_p = \sqrt{\dfrac{0.6(1-0.6)}{800}}$

$\sigma_p = \sqrt{\dfrac{0.6(0.4)}{800}}$

$\sigma_p = \sqrt{\dfrac{0.24}{800}}$

$\sigma_p = \sqrt{3 \times 10^{-4}}$

$\mathbf{\sigma_p =0.01732}$

7 0

3 years ago

A golfball is hit from the ground with an initial velocity of 200 ft/sec. The horizontal distance that the golfball will travel,

algol13

Answer:

The golfball launched with an initial velocity of 200ft/s will travel the maximum possible distance which is 1250 ft when it is hit at an angle of $\pi/4$ .

Step-by-step explanation:

The formula from the maximum distance of a projectile with initial height h=0, is:

$d(\theta)=\frac{v_i^2sin(2\theta)}{g}$

Where $v_i$ is the initial velocity.

In the closed interval method, the first step is to find the values of the function in the critical points in the interval which is $[0, \pi/2]$ . The critical points of the function are those who make $d'(\theta)=0$ :

$d(\theta)=\frac{v_i^2\sin(2\theta)}{g}\\d'(\theta)=\frac{v_i^2\cos(2\theta)}{g}*(2)\\d'(\theta)=\frac{2v_i^2\cos(2\theta)}{g}$

$d'(\theta)=0\\\frac{2v_i^2\cos(2\theta)}{g}=0\\\cos(2\theta)=0\\2\theta=\pi/2,3\pi/2,5\pi/2,...\\\theta=\pi/4,3\pi/4,5\pi/4,...$

The critical value inside the interval is $\pi/4$ .

$d(\theta)=\frac{v_i^2sin(2\theta)}{g}\\d(\pi/4)=\frac{v_i^2sin(2(\pi/4))}{g}\\d(\pi/4)=\frac{v_i^2sin(\pi/2)}{g}\\d(\pi/4)=\frac{v_i^2(1)}{g}\\d(\pi/4)=\frac{(200)^2}{32}\\d(\pi/4)=\frac{40000}{32}\\d(\pi/4)=1250ft$

The second step is to find the values of the function at the endpoints of the interval:

$d(\theta)=\frac{v_i^2sin(2\theta)}{g}\\\theta=0\\d(0)=\frac{v_i^2sin(2(0))}{g}\\d(0)=\frac{v_i^2(0)}{g}=0ft\\\theta=\pi/2\\d(\pi/2)=\frac{v_i^2sin(2(\pi/2))}{g}\\d(\pi/2)=\frac{v_i^2sin(\pi)}{g}\\d(\pi/2)=\frac{v_i^2(0)}{g}=0ft$

The biggest value of f is gived by $\pi/4$ , therefore $\pi/4$ is the absolute maximum.

In the context of the problem, the golfball launched with an initial velocity of 200ft/s will travel the maximum possible distance which is 1250 ft when it is hit at an angle of $\pi/4$ .

4 0

3 years ago

Which table represents the function y = 4x - 3?

dezoksy [38]

Answer:

is the first one

Step-by-step explanation:

so i did 4x0=0 -3=-3

so first y should be -3

4x1-3=1

second y should be 1

4x2=8-3=5

third y should be 5

8 0

3 years ago

Read 2 more answers

Ebwgqf<br> vqefabtq ebbqr

Sedaia [141]

Answer:

huh

Step-by-step explanation:

7 0

2 years ago

Enter the value of x that makes the equation - 15(x + 11) + 14x = -60 true.

eimsori [14]

Answer:x=-105

Step-by-step explanation:-15x-165+14x=-60<=>-15x+14x=-60+165<=>-x=105<=>x=-105

8 0

2 years ago