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mezya [45]
2 years ago
7

Identify the vertex and directrix of each. y = x2 + 2x - 4

Mathematics
1 answer:
sergey [27]2 years ago
8 0

Answer:

See below

Step-by-step explanation:

<u>Convert equation to vertex form </u>y=(x-h)^2+k<u> by completing the square:</u>

y=x^2+2x-4

y+5=x^2+2x-4+5

y+5=x^2+2x+1

y+5=(x+1)^2

y=(x+1)^2-5

<u>Vertex:</u>

<u />(h,k)\rightarrow(-1,-5)<u />

<u>Directrix:</u>

<u />y=k-\frac{1}{4a}\rightarrow y=-5-\frac{1}{4(1)}\rightarrow y=-\frac{21}{4}<u />

<u />

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Point P is at the origin. Then Point P is moved 4 units to the right and 5 units up.
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Indicate the equation of the line, in standard form, that passes through (2, -4) and has a slope of 3/5. Enter your answer into
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The equation of the line is  y = (3/5)x + 26/5

<u>Step-by-step explanation:</u>

  • The line passes through the point (2,-4).
  • The line has the slope of 3/5.

To find the equation of the line passing through a point and given its slope, the slope-intercept form is used to find its equation.

<u>The equation of the line when a point and slope is given :</u>

⇒ (y-y1) = m(x-x1)

where,

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Therefore, the equation of the line can be framed by,

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Take the denominator 5 to the left side of the equation.

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⇒ 5y+20 = 3x -6

⇒ 5y = 3x-26

Divide by 5 on both sides of the equation,

⇒ y = (3/5)x + 26/5

Therefore, the equation of the line is  y = (3/5)x + 26/5

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