Question

In ΔJKL, the measure of ∠L=90°, LJ = 33 feet, and JK = 58 feet. Find the measure of ∠K to the nearest tenth of a degree.

Answer 1

Answer:

∠K = 29.6°

Step-by-step explanation:

The diagram is shown below:

From the triangle, JK = 58 feet and LJ = 33 feet. ∠L = 90°.

So, the triangle ΔJKL is a right angled triangle.

Now, for the triangle ΔJKL, tan of the angle K is given as:

$tan(K)=\frac{JL}{KL}=\frac{33}{58}$

∴∠K = $tan^{-1} (\frac{33}{58})=29.6$°

So, the measure of angle K is ∠K = 29.6° to the nearest tenth of a degree.