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Minchanka [31]
2 years ago
8

The formula for the volume of a cylinder is V = π r^2 h. Solve V= π r^2 h for h, the height of the cylinder.

Mathematics
1 answer:
Alex17521 [72]2 years ago
6 0

Answer:

C

Step-by-step explanation:

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- 20 + 5p - 7z<br><br> 8x - 20y - 10
Vladimir79 [104]

Answer:

Step-by-step explanation:

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6 0
3 years ago
5x=3x+20 can you answer this and show how you got the answer
charle [14.2K]
5x=3x+20
5x-3x=3x-3x+20
2x=20
2x/2=20/2
X=10   Hope this helped!

-Twix
8 0
3 years ago
Read 2 more answers
Find the area of the figure. <br><br> A = <br><br> Is it m, m2, or m3
enot [183]

Answer:

348 m^2

Step-by-step explanation:

The figure is made up of a rectangle 24 m by 12 m, and a triangle with a 24 m base and a 5 m height.

A = LW + bh/2

A = 24 m * 12 m + (24 m)(5 m)/2

A = 288 m^2 + 60 m^2

A = 348 m^2

5 0
3 years ago
The molar mass of AlCl3 is 133.34 g/mol. How many molecules of AlCl3 are there in 2 g?
Mnenie [13.5K]

To solve this problem, we have to apply mole-concept to this and we would need the molar mass of AlCl3.  2g of AlCl3 contains 9.034*10^21 molecules.

<h3>Number of Molecules in 2g of AlCl3</h3>

The molar mass of AlCl3 is given as 133.34g/mol

Data;

  • mass = 2g
  • molar mass = 133.34g/mol

Using the mole concept, we can equate the molar mass to the number of molecules present in the entity.

133.34g = 6.023*10^2^3

If we equate this

133.34g = 6.023*10^2^3\\2g = x molecules\\x = \frac{2*6.023*10^2^3}{133.34} \\x = 9.034*10^2^1 molecules

From the calculations above, 2g of AlCl3 contains 9.034*10^21 molecules.

Learn more on mole concept here;

brainly.com/question/21150359

#SPJ1

5 0
2 years ago
Using sigma notation write the geographic series: 6+12+24+48+96
Alika [10]

Answer:

$$\sum_{n=1}^{5} 6(2^{n-1}) $$

Step-by-step explanation:

6 + 12 + 24 + 48 + 96 =

= 6 + 6 * 2 + 6 * 4 + 6 * 8 + 6 * 16

= 6 + 6 * 2^2 + 6 * 2^2 + 6 * 2^3 + 6 * 2 * 4

= 6 * 2^(n - 1)

$$\sum_{n=1}^{5} 6(2^{n-1}) $$

4 0
3 years ago
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