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aleksandr82 [10.1K]
2 years ago
10

In a mathematics test given to 15 students, the following marks (out of 100) se recorded. Find the mean 41,39,48,52,46,62,54,40,

96,52.98,40,42,52.60​
Mathematics
2 answers:
fgiga [73]2 years ago
8 0

Answer:

54.8

Step-by-step explanation:

41+39+48+52+46+62+54+40+96+52+98+40+42+52+60 = 822

822/15= 54.8

Please mark this as Brainliest if it helped you

Gre4nikov [31]2 years ago
7 0

Hey there! I'll try to provide you with my best answer.

Answer: 51.198 but if the question asks approximation then it's 51 .

In order to find we the mean, we add them all and divide the total by how many numbers there were. So,

(41 + 39 + 48 + 52 + 46 + 62 + 54 + 40 + 96 + 52.98 + 40 + 42 + 52.60​)/13

= 665.58/13

= 51.198

Approximately its 51

Hope it helps! ^^

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LekaFEV [45]
Annual Percentage rate (APR) is calculated by the formula:

APR = 72i / {3P(n+1) + i(n-1)}

where:

i = Interest Rate
P = principal amount borrowed
n = number of months of the loan

Given: 

Interest rate = $782.96
Principal amount = $4,000
number of months = 36 months

Substitute the given to the formula:

APR = 72(782.96) / [{3(4000)(36+1)} +  {782.96(36-1)}]
APR = 56,373.12 / {444,000 + 27,403.60}
APR = 56,373.12 / 471,403.60
APR = .1196 X 100    ⇒ Multiply by 100 to get the percentage
APR = 11.96% or 12%  (c)

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3 years ago
Can someone help me I don’t know the answer
user100 [1]

Answer:

P

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6 0
2 years ago
645 divided by 43 I need help please
adell [148]

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4 0
3 years ago
Find the value of x.<br> A) 71 <br> B) 72 <br> C) 73 <br> D) 75
natita [175]
146° + (-39 +x)° = 180°

Subtract 146° on both sides.

(-39 +x)° = 180° - 146°

(-39 +x)° = 34°

(x - 39)° = 34°

Add 39° on both sides

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Your final answer is C) 73.
3 0
3 years ago
Read 2 more answers
Rewrite with only sin x and cos x.
Annette [7]

Option A

\cos 3 x=\cos x-4 \cos x \sin ^{2} x

<em><u>Solution:</u></em>

Given that we have to rewrite with only sin x and cos x

Given is cos 3x

cos 3x = cos(x + 2x)

We know that,

\cos (a+b)=\cos a \cos b-\sin a \sin b

Therefore,

\cos (x+2 x)=\cos x \cos 2 x-\sin x \sin 2 x  ---- eqn 1

We know that,

\sin 2 x=2 \sin x \cos x

\cos 2 x=\cos ^{2} x-\sin ^{2} x

Substituting these values in eqn 1

\cos (x+2 x)=\cos x\left(\cos ^{2} x-\sin ^{2} x\right)-\sin x(2 \sin x \cos x)  -------- eqn 2

We know that,

\cos ^{2} x-\sin ^{2} x=1-2 \sin ^{2} x

Applying this in above eqn 2, we get

\cos (x+2 x)=\cos x\left(1-2 \sin ^{2} x\right)-\sin x(2 \sin x \cos x)

\begin{aligned}&\cos (x+2 x)=\cos x-2 \sin ^{2} x \cos x-2 \sin ^{2} x \cos x\\\\&\cos (x+2 x)=\cos x-4 \sin ^{2} x \cos x\end{aligned}

\cos (x+2 x)=\cos x-4 \cos x \sin ^{2} x

Therefore,

\cos 3 x=\cos x-4 \cos x \sin ^{2} x

Option A is correct

7 0
3 years ago
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