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2 years ago

I need help plz answer fast

Mathematics

1 answer:

Ksivusya [100]2 years ago

4 0

Answer:

Reflecting a point across the y-axis -> changes the sign of the x-coordinate

Reflecting a point across both axes -> changes the sign of both coordinates

Reflecting a point across the x-axis -> changes the sign of the y-coordinate

Step-by-step explanation:

Reflections:

The rule to reflect a point across the y-axis is (-x, y), meaning that the x-coordinate's sign changes.
Reflecting a point across both axes is the same thing as rotating it 180 degrees, so the rule is (-x, -y). This means that both coordinates' signs change.
Reflecting a point across the x-axis is (x, -y), meaning that the y-coordinate's sign changes.

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Kim bought a hat. in California. The hat cost $15 before the 8% sales tax was applied. How much did Kim pay for the hat after ta

gizmo_the_mogwai [7]

Answer:

$16.2

Step-by-step explanation:

15 x .08 [wonder how i got .08? 8% = 0.8]

= 1.2

here's where most people mess up, they usually forget to add the tax to the original cost.

15 + 1.2=

$16.2

7 0

2 years ago

If s(x)=x-7 and t(x) =4x^2+3 which expression is equivalent to (t×s)(x)

marshall27 [118]

Answer:

$\large\boxed{(t\times s)(x)=4x^3-28x^2+3x-21}$

Step-by-step explanation:

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8 0

3 years ago

Solve the system by the elimination method.

Vika [28.1K]

10x + 2y - 6 = 0

Multiply 5x + y - 3 = 0 by 2

2(5x + y - 3 = 0) = 10x + 2y - 6 = 0

7 0

3 years ago

Read 2 more answers

A strobe light is located at the center of a square dance room. the rotating light is 40 feet from each of the square walls and

Effectus [21]

The equation of the rotating light is an illustration of a secant function

The equation that represents the distance between the center of the circle and the light source is $d(t) = 40\sec(\frac{\pi}{3}t)$

<h3>How to determine the equation</h3>

The equation is a secant function represented by

$y =A\sec(Bt)$

Where:

A represents the amplitude

So, we have:

$A = 40$ --- the distance of the light from each square wall

B represents the period, and it is calculated as:

$B = \frac{2\pi}{T}$

The light completes its full rotation every 6 seconds.

This means that,

T = 6

So, we have:

$B = \frac{2\pi}{6}$

Simplify

$B = \frac{\pi}{3}$

Substitute values for A and B in $y =A\sec(Bt)$

$y = 40\sec(\frac{\pi}{3}t)$

Rewrite as a function

$d(t) = 40\sec(\frac{\pi}{3}t)$

Hence, the equation that represents the distance between the center of the circle and the light source is $d(t) = 40\sec(\frac{\pi}{3}t)$

Read more about trigonometry functions at:

brainly.com/question/1143565

5 0

2 years ago

How do I find the area

inn [45]

Wasssaa,

Steps:

To find the area of a triangle you multiply the base times the height, in this case the is (19m)
and the height is (11m), after you multipy those numbers you divide by (2)
$(19m \times 11m) \div 2$
$\frac{209 }{2}$

Answer:
$104.5sq \: m$
Hope this helped you
:D

8 0

3 years ago