Can someone help (Its a photo) ill give brain list

Solve an equation x/17= -4

Rainbow [258]

Answer:

-68

Step-by-step explanation:

X/17=-4

X=-68

So the answer is -68

6 0

3 years ago

(2x)/(x-1)<br> Find the derivative using quotient rule

irina1246 [14]

Answer:

Step-by-step explanation:

see pic below for quotient rule

$\frac{(2x)'(x-1)-(2x)(x-1)'}{(x-1)^2}=\frac{2(x-1)-2x}{(x-1)^2}=\frac{2x-2-2x}{(x-1)^2}=-\frac{2}{(x-1)^2}$

5 0

3 years ago

Calculate the perimeter of a square whose diagonal measures 29 dm.

mojhsa [17]

Answer:

$4\sqrt{420.5}$ dm

Step-by-step explanation:

A square's diagonal cuts across the square, making two right triangles where the diagonal is the hypotenuse.

We have a right triangle with a hypotenuse of 29, and two legs that are the same length (because they are sides of a square)

So, we can use pythagoreans theorem to find the lengths of the legs, or sides of the square.

$a^2 + a^2 = 29^2$

$2a^2 = 841$

$a^2 = 420.5\\$

$a = \sqrt{420.5}$

Now that we have a side length of $\sqrt{420.5}$ , we just have to multiply that by 4, since a square has 4 sides. This leaves us with a final perimeter of:

$4\sqrt{420.5}$

8 0

4 years ago

A study found that the average stopping distance of a school bus traveling 50 mph was 264 feet. a group of automotive engineers

lutik1710 [3]

Answer:

Step-by-step explanation:

Given that a study found that the average stopping distance of a school bus traveling 50 mph was 264 feet.

Sample taken showed the following results

$n=40\\\bar x =262.3 feet\\Std dev = \sigma= 3 ft$

Since population std deviation is known and sample size is large, z test can be used.

$H_0: \bar x=264\\H_a: \bar x$

(Left tailed test)

Mean difference = $264-262.3 = 1.7$

Std error = $\frac{\sigma}{\sqrt{n} } \\=\frac{3}{\sqrt{40} } \\=0.474$

Z = test statistic = mean diff/std error

= $\frac{1.7}{0.474} \\=3.584$

p value = 0.00017

Since p < alpha our 0.05 we reject null hypothesis

There is evidence to show that mean is less than 264 feet

(Assumptions:

Sample are randomly drawn

Sample represents the population

4 0

3 years ago

eu (european union) countries report that 46% of their labor force is female. The United Nations wnats to determine if the perce

Brrunno [24]

Answer:

Step-by-step explanation:

The question is incomplete. The complete question is:

EU (European Union) countries report that 46% of their labor force is female. The United Nations wants to determine if the percentage of females in the U.S. labor force is the same. Based on a sample of 500 employment records, representatives from the United States Department of Labor found that the 95% confidence interval for the proportion of females in the U.S. labor force is 0.357 to 0.443. If the Department of Labor wishes to tighten its interval, they should:

A. increase the confidence level

B. decrease the sample size

C. increase the sample size

D. Both A and B

E. Both A and C

Solution:

Confidence interval for population proportion is written as

Sample proportion ± margin of error

Where sample proportion is the point estimate for the population proportion.

Margin of error = z × √pq/n

The z score for 95% confidence level is 1.96

p = 46/100 = 0.46

q = 1 - p = 1 - 0.46

q = 0.54

n = 500

Margin of error = 1.96√0.46 × 0.54/500 = 0.044

To tighten it's interval, the margin of error needs to be reduced.

If we increase the confidence level, say to 99%, z = 2.58

Then

Margin of error = 2.58√0.46 × 0.54/500 = 0.058

It increased

Also, If we increase the sample size, say to 700, then

Margin of error = 1.96√0.46 × 0.54/700 = 0.037

It has reduced

Therefore, the correct options is

C. increase the sample size

8 0

3 years ago