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meriva
2 years ago
10

ANSWER FOR 30 POINTS

Mathematics
1 answer:
butalik [34]2 years ago
6 0

Answer:

one solution.

Step-by-step explanation:

using elimination, u can get one solution

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Un pueblo tenía 13.578 habitantes en 1970. En 1988 la población se incrementó 1,5 veces con respecto a 1970 y en 2001 se increme
igor_vitrenko [27]

Answer:

En 2001 el pueblo poseía 45.826 habitantes.

Step-by-step explanation:

Un pueblo tenía 13.578 habitantes en 1970. En 1988 la población se incrementó 1,5 veces con respecto a 1970. Para calcular entonces la población en 1988 debes realizar el siguiente cálculo:

13.578*1,5= 20.367

Por lo que en 1988 el pueblo poseía 20.367 habitantes.

En 2001 se incrementó la población 2,25 veces en relación a 1988. Para calcular entonces la población en 2001 debes realizar el siguiente cálculo:

20.367* 2,25= 45.825,75≅ 45.826

Por lo que <u><em>en 2001 el pueblo poseía 45.826 habitantes.</em></u>

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2 years ago
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alexgriva [62]
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3 years ago
A parking lot charges $2 per hour for the first 4 hours, then $3 per hour after that. Which equation(s) describes the total cost
Anon25 [30]

Answer:

A.

Step-by-step explanation:

2/hour

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Equation =8+3x

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3 years ago
Which of the following is a unit rate?
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Answer:

2

Step-by-step explanation:

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