All categories

3 years ago

I need help on math please

Mathematics

1 answer:

katen-ka-za [31]3 years ago

7 0

Answer:

if i correct pls comment I think it is 33

You might be interested in

At&t stadium home of the dallas cowboys of the NFL, seats approximately 11,200 more fans than Gillette Stadium, hime of the

Mamont248 [21]

Answer:

At&t Stadium (Dallas cowboys) = 80,000 seats

CenturyLink Field (Seattle Seahawks) = 65,000 seats

Gillette Stadium (New England Patriots) = 68,800 seats

Step-by-step explanation:

The three stadiums all together have a total of 213,800 seats

We'll call X the Gillette Stadium seats. We already had that the At&t stadium had X seats + 11,200 seats. And also we knew that the CenturyLink Field had X seats - 3,800 seats. The we can write the following equation,

X + (X + 11,200) + (X - 3,800) = 213,800 seats (the total of seats of the 3 stadiums together). We need to find the value for X, that represents the Gillette stadium seats

Then we can write X + X + 11,200 + X - 3,800 = 213,800 seats,

This is 3X + 11,200 - 3,800 = 213,800,

3X + 7,400 = 213,800,

3X = 213,800 - 7,400,

X = 206,400/3 seats

X = 68,800 seats

As At&t is X + 11,200 seats, then it accommodates 80,000 people

And as CenturyLink Field is X - 3,800, it accommodates 65,000 people

7 0

3 years ago

Find the first four terms in the sequence an = 15 + 6n

Alona [7]

Answer:

21, 27, 33, 39 and so on....

6 0

3 years ago

Find the angle between the given vectors to the nearest tenth of a degree. u = <-5, -4>, v = <-4, -3> (1 point)

sesenic [268]

Angle between $u = -5i-4j , v=-4i-3j$ is $x =0$ ° .

<u>Step-by-step explanation:</u>

We have , two vectors u = <-5, -4>, v = <-4, -3> or , $u = -5i-4j , v=-4i-3j$

We need to find angle between these two vectors . Let's find out:

We know that dot product of two vectors is defined as :

$u.v =|u|(|v|)cosx$ , where x is angle between u & v !

⇒ $u.v =|u|(|v|)cosx$

⇒ $cosx =\frac{u.v}{|u|(|v|)}$

Now , $u.v = (-5i-4j)(-4i-3j)$

⇒ $u.v = (-5i-4j)(-4i)-(-5i-4j)(3j)$

⇒ $u.v = 20+12$ { $i(j) = j(i) =0$ }

⇒ $u.v = 32$

Now , Modulus of any vector $r = xi+yj$ is $|r| = \sqrt{x^{2}+y^{2}}$ So ,

$|u| = \sqrt{(-5)^{2}+(-4)^{2}} = \sqrt{25+16} = \sqrt{41} \\\\|v| = \sqrt{(-4)^{2}+(-3)^{2}} = \sqrt{16+9} = \sqrt{25} = 5$

Putting all these values in equation $cosx =\frac{u.v}{|u|(|v|)}$ we get:

⇒ $cosx =\frac{32}{5(\sqrt{41})}$

⇒ $cos^{-1}(cosx) =cos^{-1}(\frac{32}{5(6.4)})$

⇒ $x =cos^{-1}(1)$ { $cos0 = 1$ }

⇒ $x =0$ °

Therefore , Angle between $u = -5i-4j , v=-4i-3j$ is $x =0$ ° .

8 0

3 years ago

Which of these chess pieces starts on squares a1 and h1, and a8 and h8?

Stella [2.4K]

Answer: Each player has two rooks (formerly also known as castles), which begin the game on the corner squares a1 and h1 for White, a8 and h8 for Black.

Step-by-step explanation: Mark me as brainliest

4 0

3 years ago

What is the awnser to this question

Alborosie

Answer is A and C because they equal to 3(10-c)

4 0

3 years ago