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n200080 [17]
3 years ago
6

How to solve 2(2d+4)=-3(d+2) ?

Mathematics
2 answers:
adoni [48]3 years ago
7 0
2(2d+4)=-3(d+2)
4d+8=-3d-6
4d+3d=-6-8
7d=-14
d=-14/7
d=-2
grandymaker [24]3 years ago
5 0
Solve for d by simplifying both sides of the equation, then isolating the variable.

d=-2
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Use the law of syllogism to form a conclusion from the given premises. Premise 1: If a polygon was translated to the right, then
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<span>Premise 1: If a polygon was translated to the right, then its image is congruent to its pre-image.

In symbols: p => q

Premise 2: If an image is congruent to its pre-image, then a rigid transformation was performed.

In symbols: q => r

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(p => q) and (q => r) => q => r

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Reil [10]

Answer:  3a = (0, 1)       3b = (2, 1)      3c = (2.5, 1)      3d = (1.6, 1)

               4a = (2, 3.5)             4b = (2, 3)           4c = (2, 5.375)

<u>Step-by-step explanation:</u>

The length of AB is 6 and is horizontal (affects the x-coordinate)

3a)\quad 6\bigg(\dfrac{1}{2}\bigg)\quad =3\qquad \qquad A(-2, 1) +(3, 0)= C(1,1)\\\\\\3b)\quad 6\bigg(\dfrac{2}{3}\bigg)\quad =4\qquad \qquad A(-2, 1) +(4,0)= C(2,1)\\\\\\3c)\quad 6\bigg(\dfrac{3}{4}\bigg)\quad =\dfrac{9}{2}\qquad \qquad A(-2, 1) +(4.5,0)= C(2.5,1)

3d)\quad 6\bigg(\dfrac{3}{5}\bigg)\quad =\dfrac{18}{5}\qquad \qquad A(-2, 1) +(3.6,0)= C(1.6,1)

***********************************************************************************

The length of AB is 5 and is vertical (affects the y-coordinate)

4a)\quad 5\bigg(\dfrac{1}{2}\bigg)\quad =\dfrac{5}{2}\qquad \qquad A(2, 1) +(0,2.5)= C(2,3.5)\\\\\\4b)\quad 5\bigg(\dfrac{2}{5}\bigg)\quad =2\qquad \qquad A(2, 1) +(0,2)= C(2,3)\\\\\\4c)\quad 5\bigg(\dfrac{7}{8}\bigg)\quad =\dfrac{35}{8}\qquad \qquad A(2, 1) +(0,4.375)= C(2,5.375)

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Find the 3rd term in (x-9)^7
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The 3rd term would be the parenthesis to the 7th power.

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