Answer: The mid-point of AC easy to calculate.
It is at ((5+3)/2,(5−1)/2)=(4,2) .
What you really asked was the coordinates of the point 3/4 of the way from A to C, and the calculation is very similar. I think of it as giving a “weighting” to the nearest point. So in this case we give a weighting of 3 to point C and 1 to point A.
Then =((5+3∗3)/4,(5−1∗3)/4)
So =(3½,½) .
CHECK:
Distance
2=(5−3½)2+(5−½)2
=(3/2)2+(9/2)2=9/4+81/4
=90/4
So the distance =310‾‾‾√/2
And the distance
2=(3½−3)2+(½+1)2
=1/4+9/4=10/4
And so the distance BC is 10‾‾‾√/2 which is indeed one third of the distance AB.
Step-by-step explanation:
His estimate is not reasonable because he would have to be more descriptive in order to have his answer justified
Answer:
The solution to the equation is:
- <u>x = 2.5</u> or <u>x = 5/2</u>
Step-by-step explanation:
To find the solution to the equation, you only must operate the equation until you clear the x variable, with the next steps:
And we solve:
- 4x + 28 = 38 (we multiply 4 by x and 7)
- 4x = 38 - 28 (we pass the +28 to subtract to the right side of the equality and operate)
- x = 10 / 4 (we pass the 4 that is multiplying to divide to the right side of the equality)
- <u>x = 2.5</u> (we divide)
As you can see, <u><em>the solution of the equation is </em></u><u><em>x = 2.5</em></u><u><em> or </em></u><u><em>x = 5/2</em></u>