The formula for the volume of a cone is V =1/3 pi*r^2h. If the radius (r) is doubled and

How do i find the volume of these similar solids? round to the nearest tenth HELP

FromTheMoon [43]

Answer:

The volume of the larger solid is $592.6\ mm^3$

Step-by-step explanation:

The question is

If these solids are similar, find the volume of the larger solid

step 1

Find the scale factor

we know that

If two solids are similar, then the ratio of its corresponding sides is proportional and this ratio is called the scale factor

Let

x ----> the height of the larger solid in mm

y ----> the height of the smaller solid in mm

z ---> the scale factor

$z=\frac{x}{y}$

we have

$x=4\ mm\\y=3\ mm$

substitute

$z=\frac{4}{3}$ ---> scale factor

step 2

Find the volume of the larger solid

we know that

If two solids are similar, then the ratio of its volumes is equal to the scale factor elevated to the cube

Let

x ----> the volume of the larger solid in cubic millimeters

y ----> the volume of the smaller solid in in cubic millimeters

z ---> the scale factor

$z^3=\frac{x}{y}$

we have

$z=\frac{4}{3}$

$y=250\ mm^3$

substitute the values

$(\frac{4}{3})^3=\frac{x}{250}$

solve for x

$(\frac{64}{27})=\frac{x}{250}$

$x=250(\frac{64}{27})$

$x=592.6\ mm^3$

4 0

3 years ago

Drag the values into the boxes to classify each number as rational or irrational. picture below pls help quick.

larisa [96]

Answer:

Step-by-step explanation:

Rational numbers;

Numbers which can be written in the form of $\frac{p}{q}$ or repeating decimal numbers are the rational numbers.

Examples : 1, 2, $\frac{2}{3}$

Irrational numbers:

Numbers which can't be written in he form of a fraction or non repeating decimal numbers are the Irrational number.

Example: $\sqrt{8},\pi,\sqrt{\frac{8}{21} }$

From the given numbers,

Rational numbers: $\frac{11}{3}$ , 6.25, 0.01045, $\sqrt{\frac{16}{81} }$ , 0.424242....

Irrational numbers: $\sqrt{48}, \sqrt{\frac{3}{16} }$

6 0

3 years ago

In the diagram below DE is parallel to XY. What is the value of y?

kirza4 [7]

this would be 94 hope it helps

3 0

3 years ago

Read 2 more answers

SAT scores are normed so that, in any year, the mean of the verbal or math test should be 500 and the standard deviation 100. as

vovangra [49]

Answer:

a) $P(X>625)=P(\frac{X-\mu}{\sigma}>\frac{625-\mu}{\sigma})=P(Z>\frac{625-500}{100})=P(Z>1.25)$

$P(Z>1.25)=1-P(Z$

b) $P(400$

$P(-1$

c) $z=-0.842$

And if we solve for a we got

$a=500 -0.842*100=415.8$

So the value of height that separates the bottom 20% of data from the top 80% is 415.8.

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".

Part a

Let X the random variable that represent the SAT scores of a population, and for this case we know the distribution for X is given by:

$X \sim N(500,100)$

Where $\mu=500$ and $\sigma=100$

We are interested on this probability

$P(X>625)$

And the best way to solve this problem is using the normal standard distribution and the z score given by:

$z=\frac{x-\mu}{\sigma}$

If we apply this formula to our probability we got this:

$P(X>625)=P(\frac{X-\mu}{\sigma}>\frac{625-\mu}{\sigma})=P(Z>\frac{625-500}{100})=P(Z>1.25)$

And we can find this probability using the complement rule and with the normal standard table or excel:

$P(Z>1.25)=1-P(Z$

Part b

We are interested on this probability

$P(400$

And the best way to solve this problem is using the normal standard distribution and the z score given by:

$z=\frac{x-\mu}{\sigma}$

If we apply this formula to our probability we got this:

$P(400$

And we can find this probability with this difference:

$P(-1$

And in order to find these probabilities we can find tables for the normal standard distribution, excel or a calculator.

$P(-1$

Part c

For this part we want to find a value a, such that we satisfy this condition:

$P(X>a)=0.8$ (a)

$P(X$ (b)

Both conditions are equivalent on this case. We can use the z score again in order to find the value a.

As we can see on the figure attached the z value that satisfy the condition with 0.2 of the area on the left and 0.8 of the area on the right it's z=-0.842. On this case P(Z<-0.842)=0.2 and P(Z>-0.842)=0.8

If we use condition (b) from previous we have this:

$P(X$

$P(z$

But we know which value of z satisfy the previous equation so then we can do this:

$z=-0.842$

And if we solve for a we got

$a=500 -0.842*100=415.8$

So the value of height that separates the bottom 20% of data from the top 80% is 415.8.

8 0

2 years ago

Whats x? 8+x=12 will give brainliest

nikklg [1K]

Answer:

X = 4

Step-by-step explanation:

3 0

3 years ago