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andrezito [222]
2 years ago
6

For males in a certain town, the systolic blood pressure is normally distributed with a mean of 125 and a standard deviation of

8. Using the empirical rule, what percentage of males in the town have a systolic blood pressure between 109 and 141?
Mathematics
1 answer:
makkiz [27]2 years ago
5 0

95% have a systolic blood pressure between 109 and 141

Empirical rule states that for a normal distribution, 68% are within one standard deviation from the mean, 95% are within two standard deviation from the mean and 99.7% are within three standard deviation from the mean.

Given that mean (μ) = 125, standard deviation (σ) = 8.

68% are within one standard deviation = μ ± σ = 125 ± 8 = (117, 133)

95% are within two standard deviation = μ ± 2σ = 125 ± 2*8 = (109, 141)

95% have a systolic blood pressure between 109 and 141

Find out more on empirical rule at: brainly.com/question/10093236

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Help! What is the average rate of change of f(x)=x^2+3x+6 over the interval -3 less-than-or-equal-to x less-than-or-equal-to 3?
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Answer:

The average rate of change of the function over the interval is 5.

Step-by-step explanation:

Average rate of change of a function:

The average rate of change of a function f(x) over an interval [a,b] is given by:

A = \frac{f(b)-f(a)}{b-a}

Interval -3 less-than-or-equal-to x less-than-or-equal-to 3

This means that a = -3, b = 3

f(x) = x^2 + 3x + 6

So

f(b) = f(3) = (3)^2 + 3(3) + 6 = 9 + 9 + 6 = 24

f(a) = f(-3) = (-3)^2 + 3(-3) + 6 = 9 - 9 + 6 = 6

Average rate of change

A = \frac{f(b)-f(a)}{b-a} = \frac{24+6}{3-(-3)} = \frac{30}{6} = 5

The average rate of change of the function over the interval is 5.

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