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andrezito [222]
2 years ago
6

For males in a certain town, the systolic blood pressure is normally distributed with a mean of 125 and a standard deviation of

8. Using the empirical rule, what percentage of males in the town have a systolic blood pressure between 109 and 141?
Mathematics
1 answer:
makkiz [27]2 years ago
5 0

95% have a systolic blood pressure between 109 and 141

Empirical rule states that for a normal distribution, 68% are within one standard deviation from the mean, 95% are within two standard deviation from the mean and 99.7% are within three standard deviation from the mean.

Given that mean (μ) = 125, standard deviation (σ) = 8.

68% are within one standard deviation = μ ± σ = 125 ± 8 = (117, 133)

95% are within two standard deviation = μ ± 2σ = 125 ± 2*8 = (109, 141)

95% have a systolic blood pressure between 109 and 141

Find out more on empirical rule at: brainly.com/question/10093236

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Answer:

<em>95% of confidence interval for the Population</em>

<em>( 6.1386 , 6.8614)</em>

Step-by-step explanation:

<u><em>Step( i ):-</em></u>

<em>Given random sample size 'n' =85</em>

<em>Mean of the sample size x⁻ = 6.5 years</em>

<em>Standard deviation of Population = 1.7 years</em>

<em>Level of significance = 0.95 or 0.05</em>

<u><em>Step(ii):-</em></u>

<em>95% of confidence interval for the Population is determined by</em>

<em></em>(x^{-} - Z_{0.05} \frac{S.D}{\sqrt{n} } , x^{-} + Z_{0.05} \frac{S.D}{\sqrt{n} })<em></em>

<em></em>(6.5 - 1.96\frac{1.7}{\sqrt{85} } , 6.5 + 1.96 \frac{1.7}{\sqrt{85} })<em></em>

<em>( 6.5 - 0.3614 , 6.5 + 0.3614 )</em>

<em>( 6.1386 , 6.8614)</em>

<u><em>Conclusion</em></u><em>:-</em>

<em>95% of confidence interval for the Population</em>

<em>( 6.1386 , 6.8614)</em>

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