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miskamm [114]
3 years ago
9

Box A contains 5 dark chocolates and

Mathematics
2 answers:
Dmitry_Shevchenko [17]3 years ago
6 0

Answer:

\frac{1}{3}

Step-by-step explanation:

The probability of picking box A;

P(A) = 1/2

Box A has 5 dark chocolates and 10 milk chocolates.

The probability of picking a milk chocolate from box A;

P(milk in A) = \frac{10}{15} = \frac{2}{3}

P(A) and P(milk in A) = \frac{1}{2} × \frac{2}{3} = \frac{1}{3}

strojnjashka [21]3 years ago
5 0
Answer=2/3 or 66.6%
Explanation:
Total number of milk chocolate in Box A = 10
Total number of dark chocolate in Box A = 5
Total number of chocolates = 15
So probability of choosing Milk chocolate =
10/15*100
=> 2/3*100
=66.66%
Hope this helps you
Please mark this as the brainliest


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3 0
3 years ago
1- The Canada Urban Transit Association has reported that the average revenue per passenger trip during a given year was $1.55.
serg [7]

Answer:

0.5

0.9545

0.68268

0.4986501

Step-by-step explanation:

The Canada Urban Transit Association has reported that the average revenue per passenger trip during a given year was $1.55. If we assume a normal distribution and a standard deviation of 5 $0.20, what proportion of passenger trips produced a revenue of Source: American Public Transit Association, APTA 2009 Transit Fact Book, p. 35.

a. less than $1.55?

b. between $1.15 and $1.95? c. between $1.35 and $1.75? d. between $0.95 and $1.55?

Given that :

Mean (m) = 1.55

Standard deviation (s) = 0.20

a. less than $1.55?

P(x < 1.55)

USing the relation to obtain the standardized score (Z) :

Z = (x - m) / s

Z = (1.55 - 1.55) / 0.20 = 0

p(Z < 0) = 0.5 ( Z probability calculator)

b. between $1.15 and $1.95?

P(x < 1.15)

USing the relation to obtain the standardized score (Z) :

Z = (x - m) / s

Z = (1.15 - 1.55) / 0.20 = - 2

p(Z < - 2) = 0.02275 ( Z probability calculator)

P(x < 1.95)

USing the relation to obtain the standardized score (Z) :

Z = (x - m) / s

Z = (1.95 - 1.55) / 0.20 = 2

p(Z < - 2) = 0.97725 ( Z probability calculator)

0.97725 - 0.02275 = 0.9545

c. between $1.35 and $1.75?

P(x < 1.35)

USing the relation to obtain the standardized score (Z) :

Z = (x - m) / s

Z = (1.35 - 1.55) / 0.20 = - 1

p(Z < - 2) = 0.15866 ( Z probability calculator)

P(x < 1.75)

USing the relation to obtain the standardized score (Z) :

Z = (x - m) / s

Z = (1.75 - 1.55) / 0.20 = 1

p(Z < - 2) = 0.84134 ( Z probability calculator)

0.84134 - 0.15866 = 0.68268

d. between $0.95 and $1.55?

P(x < 0.95)

USing the relation to obtain the standardized score (Z) :

Z = (x - m) / s

Z = (0.95 - 1.55) / 0.20 = - 3

p(Z < - 3) = 0.0013499 ( Z probability calculator)

P(x < 1.55)

USing the relation to obtain the standardized score (Z) :

Z = (x - m) / s

Z = (1.55 - 1.55) / 0.20 = 0

p(Z < 0) = 0.5 ( Z probability calculator)

0.5 - 0.0013499 = 0.4986501

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3 years ago
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