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Dmitry [639]
2 years ago
13

Given 7x + 2 > 58, which number is not in the solution set?

Mathematics
1 answer:
Hoochie [10]2 years ago
7 0

Answer:

option 1

Step-by-step explanation:

7x + 2 > 58 ( subtract 2 from both sides )

7x > 56 ( divide both sides by 7 )

x > 8

So only values greater than 8 are in the solution set

6 is not greater than 8, then is not in the solution set

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Answer: The answer is 8.

Step-by-step explanation: The first step is to convert the expression into figures. We shall call the unknown number Y. So if we are told “the square of a number,” that means Y squared, or better still, Y^2. Further we are told “the difference between the square of a number and 40” and that can be written as;

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Next we are told that this expression is equal to 3 times that number (that is 3Y). That can now be written out as follows,

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If we move all expressions to one side of the equation, what we would have is,

Y^2 - 3Y -40 = 0

(Remember that when a positive value crosses to the other side of an equation it becomes negative and vice versa)

We now have a quadratic equation

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(Y -8) (Y + 5) = 0

Therefore Y - 8 = 0 or

Y + 5 = 0

Hence, Y = 8 or Y = -5

Since we are asked to calculate the positive solution, Y = 8

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Step-by-step explanation:

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