The closest i can think of that makes since is 1560=30(52)+b, mainly because
30 x 52 = 1560 so that's what i think it is and if im wrong sry.
Answer:
y -11 = 2(x -3)
Step-by-step explanation:
The slope of the given line is the x-coefficient: 2. The parallel line will have the same slope.
When you know the slope and a point on the line, it is convenient to use the point-slope form of the equation of a line:
y -k = m(x -h) . . . . . . line with slope m through point (h, k)
Your line's equation is ...
y -11 = 2(x -3)
That is correct since the line in T is not straight it would eventually hit the third quadrant
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The number of rabbits that there will be in 3 years is 14,580.
<h3>What is the number of rabbits in 3 years?</h3>
The growth rates of the rabbits is an exponential growth. The formula that can be used to represent the population of the rabbits in 3 years is:
f(x) = 20(3^x)
Where x represents the number of years. The number of years is 6(3 x 2)
20 x 3^6 = 14,580
To learn more about future value, please check: brainly.com/question/18760477
Answer: 4.5 miles
Explanation:
When you draw the situation you find two triangles.
1) Triangle to the east of the helicopter
a) elevation angle from the high school to the helicopter = depression angle from the helicopter to the high school = 20°
b) hypotensue = distance between the high school and the helicopter
c) opposite-leg to angle 20° = heigth of the helicopter
d) adyacent leg to the angle 20° = horizontal distance between the high school and the helicopter = x
2) triangle to the west of the helicopter
a) elevation angle from elementary school to the helicopter = depression angle from helicopter to the elementary school = 62°
b) distance between the helicopter and the elementary school = hypotenuse
c) opposite-leg to angle 62° = height of the helicopter
d) adyacent-leg to angle 62° = horizontal distance between the elementary school and the helicopter = 5 - x
3) tangent ratios
a) triangle with the helicpoter and the high school
tan 20° = Height / x ⇒ height = x tan 20°
b) triangle with the helicopter and the elementary school
tan 62° = Height / (5 - x) ⇒ height = (5 - x) tan 62°
c) equal the height from both triangles:
x tan 20° = (5 - x) tan 62°
x tan 20° = 5 tan 62° - x tan 62°
x tan 20° + x tan 62° = 5 tan 62°
x (tan 20° + tan 62°) = 5 tan 62°
⇒ x = 5 tant 62° / ( tan 20° + tan 62°)
⇒ x = 4,19 miles
=> height = x tan 20° = 4,19 tan 20° = 1,525 miles
4) Calculate the hypotenuse of this triangle:
hipotenuese ² = x² + height ² = (4.19)² + (1.525)² = 19.88 miles²
hipotenuse = 4.46 miles
Rounded to the nearest tenth = 4.5 miles
That is the distance between the helicopter and the high school.
