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2 years ago

What's the area of shape 2

Mathematics

2 answers:

goldfiish [28.3K]2 years ago

7 0

Answer:

A=486

Step-by-step explanation:

to find the area of the triangle we do

b(base) x h(height) divided by 2

In this caaaaaasseeee…

36x27/2=486

For more understanding look at the picture below ;3

hope this helped :D

sineoko [7]2 years ago

4 0

Answer:

486

Step-by-step explanation:

Formula: Area = base · height ÷ 2

So, 36(b) · 27(h) ÷ 2 = 486

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What is the value of

larisa [96]

Answer:

10.5

Step-by-step explanation:

5 0

3 years ago

Write the equation -4x^2+9y^2+32x+36y-64=0 in standard form. Please show me each step of the process!

IgorC [24]

Hey there, hope I can help!

$-4x^2+9y^2+32x+36y-64=0$

$\mathrm{Add\:}64\mathrm{\:to\:both\:sides} \ \textgreater \ 9y^2+32x+36y-4x^2=64$

$\mathrm{Factor\:out\:coefficient\:of\:square\:terms} \ \textgreater \ -4\left(x^2-8x\right)+9\left(y^2+4y\right)=64$

$\mathrm{Divide\:by\:coefficient\:of\:square\:terms:\:}4$
$-\left(x^2-8x\right)+\frac{9}{4}\left(y^2+4y\right)=16$

$\mathrm{Divide\:by\:coefficient\:of\:square\:terms:\:}9$
$-\frac{1}{9}\left(x^2-8x\right)+\frac{1}{4}\left(y^2+4y\right)=\frac{16}{9}$

$\mathrm{Convert}\:x\:\mathrm{to\:square\:form}$
$-\frac{1}{9}\left(x^2-8x+16\right)+\frac{1}{4}\left(y^2+4y\right)=\frac{16}{9}-\frac{1}{9}\left(16\right)$

$\mathrm{Convert\:to\:square\:form}$
$-\frac{1}{9}\left(x-4\right)^2+\frac{1}{4}\left(y^2+4y\right)=\frac{16}{9}-\frac{1}{9}\left(16\right)$

$\mathrm{Convert}\:y\:\mathrm{to\:square\:form}$
$-\frac{1}{9}\left(x-4\right)^2+\frac{1}{4}\left(y^2+4y+4\right)=\frac{16}{9}-\frac{1}{9}\left(16\right)+\frac{1}{4}\left(4\right)$

$\mathrm{Convert\:to\:square\:form}$
$-\frac{1}{9}\left(x-4\right)^2+\frac{1}{4}\left(y+2\right)^2=\frac{16}{9}-\frac{1}{9}\left(16\right)+\frac{1}{4}\left(4\right)$

$\mathrm{Refine\:}\frac{16}{9}-\frac{1}{9}\left(16\right)+\frac{1}{4}\left(4\right) \ \textgreater \ -\frac{1}{9}\left(x-4\right)^2+\frac{1}{4}\left(y+2\right)^2=1$

$Refine\;once\;more\;-\frac{\left(x-4\right)^2}{9}+\frac{\left(y+2\right)^2}{4}=1$

For me I used
$\frac{\left(y-k\right)^2}{a^2}-\frac{\left(x-h\right)^2}{b^2}= 1$
$As\;\mathrm{it\;\:is\:the\:standard\:equation\:for\:an\:up-down\:facing\:hyperbola}$

I know yours is an equation which is why I did not go any further because this is the standard form you are looking for. I would rewrite mine to get my hyperbola standard form. However the one I have provided is the form you need where mine would be.
$\frac{\left(y-\left(-2\right)\right)^2}{2^2}-\frac{\left(x-4\right)^2}{3^2}=1$

Hope this helps!

4 0

3 years ago

In Candyland, distance is measured in "lollygam" and "gumbo." Suppose there are 8.5 lollygam in a gumbo. Determine the number of

Alik [6]

Answer:

1.5225 gumbo squared

Step-by-step explanation:

First we know that 1 gumbo is equal to 8.5 lollygams.

To know the number of gumbo squared in 110 lollygam squared, we need to know the relation between 1 gumbo squared and 1 lollygam squared, and we do that making the square of our relation between gumbo and lollygams:

1 gumbo -> 8.5 lollygams

1 gumbo squared -> (8.5)^2 lollygams squared = 72.25 lollygams squared

Now, to know the number of gumbo squared in 110 lollygam squared, we just need to divide 110 by 72.25:

1 gumbo squared -> 72.25 lollygams squared

x gumbo squared -> 110 lollygams squared

x = 110/72.25 = 1.5225 gumbo squared

5 0

3 years ago

Can someone please help me?

Bingel [31]

So the right answer is 29.

Look at the attached picture