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2 years ago

In a class of 52 students ,the number of boys is 6/7 of the number of girls. How many are boys?

Mathematics

1 answer:

egoroff_w [7]2 years ago

8 0

Answer:

24 boys

Step-by-step explanation:

You can solve this using simultaneous equations.

You know the number of boys plus the number of girls is 52, so b + g = 52.

You also know the number of boys is 6/7 the number of girls, so b = 6/7g

Then you can substitute this into the first equation - 6/7g + g = 52, so 13/7g = 52.

Solving that equation, 52 / 13/7 = 28, so there are 28 girls.

You then work out the number of boys by doing 52- the number of girls, so 52- 28 = 24 boys

Hope this helps, let me know if you have any questions :)

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Please help thank you.

Mnenie [13.5K]

Answer:

Option D

Step-by-step explanation:

Whenever we take a square root of a number the ± sign is with it like here in the question

$x^2=20\\\\Apply\ square\ root\ on\ both\ sides\\sqrt{x^2}=\sqrt{20} \\\\The\ square\ cancels\ out\ with\ the\ root\x=\sqrt{20}$

And then x = ±4.47 which means x has two values one is +4.47 and the other is -4.47 so Option D is our answer.

7 0

2 years ago

The function f(t)= 5 tan 2 t, does not have an amplitude and has a period of π.

trasher [3.6K]

ANSWER

False

EXPLANATION

The tangent function has no amplitude because it is not bounded.

The given tangent function is

$f(t) = 5 \tan(2t)$

This is of the form

f(t)=a tan(bt)

The period is given by

$T = \frac{\pi}{ |b| }$

$T = \frac{\pi}{ |2| } = \frac{\pi}{2}$

The first statement is true but the second is false.

Hence the whole statement is false.

8 0

3 years ago

Read 2 more answers

Consider the equation below.

Korvikt [17]

Answer:

Equation in square form:

$y=3(x+5)^2-4$

Extreme value:

$(h,k)=(-5,-4)$

Step-by-step explanation:

We are given

$y=3x^2+30x+71$

we can complete square

$y=3(x^2+10x)+71$

we can use formula

$a^2+2ab+b^2=(a+b)^2$

$y=3(x^2+2\times x\times 5)+71$

now, we can add and subtract 5^2

$y=3(x^2+2\times x\times 5+5^2-5^2)+71$

$y=3(x^2+2\times x\times 5+5^2)-3\times 5^2+71$

$y=3(x+5)^2-75+71$

So, we get equation as

$y=3(x+5)^2-4$

Extreme values:

we know that this parabola

and vertex of parabola always at extreme values

so, we can compare it with

$y=a(x-h)^2+k$

where

vertex=(h,k)

now, we can compare and find h and k

$y=3(x+5)^2-4$

we get

h=-5

k=-4

so, extreme value of this equation is

$(h,k)=(-5,-4)$

6 0

3 years ago

Read 2 more answers

Noah earned v dollars over the summer. Mai earned m dollars, which is 45 dollars more than Noah did.

12345 [234]

Answer:

What is the question?

Step-by-step explanation:

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3 years ago

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if two angles of a triangle each measure 50 degrees then what is the measure of the third angle of the triangle

uranmaximum [27]

Answer:

Step-by-step explanation:

Triangles angles measure 180 degrees when added.

You have 2 at 50 which makes 100 degrees.

180 - 100 = 80 degrees

7 0

3 years ago

In a class of 52 students ,the number of boys is 6/7 of the number of girls. How many are boys? ​

In a class of 52 students ,the number of boys is 6/7 of the number of girls. How many are boys?