Answer:
error
Step-by-step explanation:
Answer: If he gives Al 42, then he gives Bob 21 and Carl 84. Do those add up to 210? 42 + 21 + 84 = 147–that’s too small! Go bigger.
Step-by-step explanation:
So Since (D) is odd, shoot right to (E). If he gives Al 60, then he gives Bob 30 and Carl 120. Does that add up to 210? Yes, yes it does. 60 + 30 + 120 = 210.
1 times 108
I Hope this helps.
1.
If no changes are made, the school has a revenue of :
625*400$/student=250,000$
2.
Assume that the school decides to reduce n*20$.
This means that there will be an increase of 50n students.
Thus there are 625 + 50n students, each paying 400-20n dollars.
The revenue is:
(625 + 50n)*(400-20n)=12.5(50+n)*20(20-n)=250(n+50)(20-n)
3.
check the options that we have,
a fee of $380 means that n=1, thus
250(n+50)(20-n)=250(1+50)(20-1)=242,250 ($)
a fee of $320 means that n=4, thus
250(n+50)(20-n)=250(4+50)(20-4)=216,000 ($)
the other options cannot be considered since neither 400-275, nor 400-325 are multiples of 20.
Conclusion, neither of the possible choices should be applied, since they will reduce the revenue.
Answer:
16 cups
Step-by-step explanation:
