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yawa3891 [41]
3 years ago
5

In a class of 52 students ,the number of boys is 6/7 of the number of girls. How many are boys? ​

Mathematics
1 answer:
egoroff_w [7]3 years ago
8 0

Answer:

24 boys

Step-by-step explanation:

You can solve this using simultaneous equations.

You know the number of boys plus the number of girls is 52, so b + g = 52.

You also know the number of boys is 6/7 the number of girls, so b = 6/7g

Then you can substitute this into the first equation - 6/7g + g = 52, so 13/7g = 52.

Solving that equation, 52 / 13/7 = 28, so there are 28 girls.

You then work out the number of boys by doing 52- the number of girls, so 52- 28 = 24 boys

Hope this helps, let me know if you have any questions :)

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In a population that is normally distributed that has a mean of 45 with a standard
elena-14-01-66 [18.8K]
I think I would be 5
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3 years ago
The ratio of cats to dogs at April's Animal Shelter was 3 to 2. How many dogs were in the shleter if there were a total of 75 ca
DochEvi [55]

Answer:

A:30

Step-by-step explanation:

because 3+2(the ratio) =5

75(the total number or both) divide by 5

so 1 ratio=15

15 x 2(the ratio of dogs)

=30

3 0
3 years ago
prakriti needs $3500 for high study in america after see.if $1=105Nrp if bank charge 3% commission how much nepali rupee should
timofeeve [1]

Answer:

356475Nrp

Step-by-step explanation:

$1=105Nrp

$3500=105×3500Nrp

=367500Nrp

Now,

Bank charges 3% commission

therefore, 3% of 367500Nrp

=3/100×367500Nrp

=11025Nrp

Then,

Required money =367500Nrp-11025Nrp

=356475Nrp

3 0
3 years ago
I apologize for all the questions I asked ​
Paul [167]

Answer:

Step-by-step explanation:

It's not clear but yeah it's fine if you ask a lot cause everytime I see this I know it's you :)

3 0
3 years ago
In a small town, the use of coal (W in tons/per
zimovet [89]

Answer:

i)W = 2500 / T

ii)  W = 500 Tons

iii) grad W(10°) = - 25î

iv) The formulation is not practical

Step-by-step explanation:

i)  Write an equation describing the use of coal

As use of coal is inversely proportional to the average monthly temperature

if  W is use of coal in tons/per month then

W(t)  =   k / T              where k is a constant of proportionality and T is the average temperature in degrees. We have to determine k from given conditions

k  =  ??   we know that when   T  =  25°    W = 100 tons  the by subtitution

W = k/T           100  =  k /25       k  =  2500 Tons*degree

Then final equation is:

W = 2500 / T

ii) Find the amount of coal when T = 5 degrees

W = 2500 / 5

W = 500 Tons

iii)

The inverse proportionality implies that W will decrease as T increase.

The vector gradient of W function is:

grad W  = DW(t)/dt î  

grad W  = - 2500/T² î

Wich agrees with the fact that W is decreasing.

And when T = 100°

grad W(10°) =  - 2500/ 100 î      ⇒  grad W(10°) = - 25î

iv) When T =  0  The quantity of coal tends to infinite and the previous formulation is not practical

5 0
3 years ago
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