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Andrei [34K]
3 years ago
8

Florian and michelle are trying to construct a triangle. florian says the side lengths could be 6, 8, and 10, and the angles of

the triangle should have measures of 37°, 53°, and 90°. michelle says the side lengths could be 7, 7, and 14, and the angles should have measures of 35°, 65°, and 80°. which of the friends has the correct measurement for the triangle? how do you know? florian has the correct side lengths because they are all even numbers. florian has the correct side lengths because the measurements fit the triangle inequality rule. michelle has the correct side lengths because they are not all even numbers. michelle has the correct side lengths because their measurements fit the triangle inequality rule.
Mathematics
2 answers:
Lera25 [3.4K]3 years ago
7 0

Answer:

B

Step-by-step explanation:

MrRa [10]3 years ago
6 0

The <em>correct answer</em> is:


Florian has the correct side lengths because the measurements fit the triangle inequality rule.


Explanation:


The triangle inequality rule states that the sum of any two sides of a triangle must be greater than the third side.


For Florian's measurements, we have:

6+8 > 10

6+10 > 8

8+10 > 6


These measurements work.


Conversely, Michelle's measurements:

7+7 = 14.


This is not greater than, so this does not work.

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I dont know the answers for these .Need help
zvonat [6]

Answer:

123°, 57°, 123°

46°, 90°

Step-by-step explanation:

28. m∠L=57° ⇒ opposite angle  m∠J=m∠L=57°

m∠M= m∠K= 180° -m∠L= 180° - 57°= 123°

29. m∠W= m∠X= 90°

m∠Y= 180° -m∠W= 180° - 134°= 46°

4 0
3 years ago
8.) Out of 600 employees, only 270 are happy with their pay. What percent is this? (Please show your work.) *
Gnom [1K]

For this case we can raise a rule of three:

600 employees -------------> 100%

270 employees -------------> x

Where the variable "x" represents the percentage of employees who are satisfied with their salary. So, we have:

x = \frac {270 * 100} {600}\\x = 45

Thus, 45% of employees are satisfied with their salary.

Answer:

45%

5 0
4 years ago
Read 2 more answers
PLEASE HELP ON 5,6,8,9<br> DUE TOMORROW
Elis [28]

5. You have correctly shown the decimal equivalents of the numbers in selection C. Those are in order. The decimal equivalents for selection D would be

... -1.33, -2.00, -1.00, -0.08, -0.07

The first of these is greater than the second of these, so this list is not in order. The correct choice is D.

6. √169 = 13, the only rational number in the lot. The correct choice is C.

8. All the numbers except the ones with radicals are rational numbers, so the appropriate choice is the one that lists the radicals only: G.

9. You have correctly plotted the points. When you connect them to make a geometric figure, you get a triangle that is 6 units high and 6 units wide. Its area will be half that of a square that is 6×6, so is 18 square units.

_____

The formula for the area of a triangle is

... A = (1/2)bh

where b is the base length of the triangle (6 units), and h is the height (6 units). Filling in the numbers you have, this is

... A = (1/2)·6·6 = 18 . . . . square units.

When you have a plot like this on a graph, it is usually pretty easy to see that the triangle area is half the area of a rectangle (or square) with the same height and width.

6 0
3 years ago
50h + 0.20s + 40 part
kozerog [31]
A.
Coefficient: 50
Variable: h
Constant: s

b.
50(25) + 0.20(300) + 40
1250 + 60 + 40
1350
Corinne earns $1350

c.
The coefficient would change because a coefficient is the number in front of a variable, and the number changed, not the variable or constant.
3 0
3 years ago
X² - 8x - 33=0<br> complete the square
Andreas93 [3]
<h2>Answer:</h2><h2></h2><h2>\boxed{x_{1}=-3} \\ \\ \boxed{x_{2}=11}</h2>

<h2>Explanation:</h2>

Step 1. Write x^2 - 8x - 33=0 in the form x^2+2ax+a^2=0

2a=-8\quad :\quad a=-4

Step 2. Add and subtract (-4)^2 to the left side of the equation

x^2-8x-33+\left(-4\right)^2-\left(-4\right)^2=0 \\ \\ \\ But: \\ \\  x^2+2ax+a^2=\left(x+a\right)^2 \\ \\ x^2-8x+\left(-4\right)^2=\left(x-4\right)^2

Step 3. Complete square

\left(x-4\right)^2-33-\left(-4\right)^2=0 \\ \\ \left(x-4\right)^2-49=0 \\ \\ (x-4)=\pm \sqrt{49} \\ \\ x-4=\pm 7 \\ \\ \boxed{x_{1}=-3} \\ \\ \boxed{x_{2}=11}

8 0
3 years ago
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