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Inessa05 [86]
2 years ago
12

Solve the system using substitution and describe your steps. x=y-3 2x+y=12

Mathematics
1 answer:
Veseljchak [2.6K]2 years ago
5 0
First you plug in for x,

2(y-3)+y=12

Then you solve for y
2y-5+y=12
-10y+y=12
-9y=12
-9y/9=12/-9
y=-1.333333333333333333333333333333333333333333333333333333333

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What scale factor was used when going from the grey triangle to the yellow triangle
sertanlavr [38]

Answer:

Scale factor of 1/3

Step-by-step explanation:

3 0
3 years ago
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Deon bought 26 pounds of rice for $11 . how many pounds of rice did he get per dollar?
ivanzaharov [21]
For $11, he bought = 26 pounds
so, for 1, it would be: 26/11 = 2.36

In short, Your Answer would be 2.36

Hope this helps!
5 0
3 years ago
6X - 2 + 5x + 7 *<br> what’s the answer?
enot [183]

Answer:

x=2.2

Step-by-step explanation:

6X - 2 + 5x + 7

add like terms

11x+5

divide 5 on both sides

x=2.2

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7 0
2 years ago
Read 2 more answers
Y=-1/4x-5 and 2x+8y=56 determine if paralllel ,nethier or perpendicular
Dominik [7]

Answer:

Parallel

Step-by-step explanation:

In the slope-intercept form (y=mx +c), the coefficient of x tells us the slope of the line.

2x +8y= 56

Let's rewrite this equation into the slope-intercept form.

8y= -2x +56

Dividing both sides by 8:

y=  -  \frac{2}{8} x +  \frac{56}{8}

y =  -  \frac{1}{4} x + 7

Slope= -¼

y= -¼x -5

Slope= -¼

Since both lines have the same slope, they are parallel to each other.

3 0
2 years ago
Recall that m(t) = (1/2)^t/h for radioactive decay, where h is the half-life. Suppose that a 500g sample of phosphorus-32 decays
katrin2010 [14]

The question is incomplete, here is the complete question:

Recall that m(t) = m.(1/2)^t/h for radioactive decay, where h is the half-life. Suppose that a 500 g sample of phosphorus-32 decays to 356 g over 7 days. Calculate the half life of the sample.

<u>Answer:</u> The half life of the sample of phosphorus-32 is 14.28days^{-1}

<u>Step-by-step explanation:</u>

The equation used to calculate the half life of the sample is given as:

m(t)=m_o(1/2)^{t/h}

where,

m(t) =  amount of sample after time 't' = 356 g

m_o = initial amount of the sample = 500 g

t = time period = 7 days

h = half life of the sample = ?

Putting values in above equation, we get:

356=500\times (\frac{1}{2})^{7/h}\\\\h=14.28days^{-1}

Hence, the half life of the sample of phosphorus-32 is 14.28days^{-1}

7 0
3 years ago
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