Answer:
SITE A
Explanation:
Given :
FACTOR___ WEIGHT _SITE A_ SITE B _SITE C
Labor Cost __ 0.25 _____92 ____82____ 84
Curr Stability _ 0.35 _____75 ___ 85____ 88
Prox Market __ 0.30 ____ 80 ____50 ___ 60
Taxes _______ 0.10 _____69 ___ 88 ___ 91
SITE A:
(0.25 * 92) + (0.35*75) + (0.30*80) + (0.10*69) = 80.15
SITE B :
(0.25 * 82) + (0.35*85) + (0.30*50) + (0.10*88) = 74.05
SITE C :
(0.25 * 84) + (0.35*88) + (0.30*60) + (0.10*91) = 78.90
Using the weighed factor model;
The based site for locating the facility is SITE A as it has the highest weighted value
Answer:
The correct answer is c) $9,000
Explanation:
If net credit sales are $300,000 and bad debt expense is estimated at 3% of net credit sales.
$300,000 x 3%= $9,000
or
$300,000 x 0.03= $9,000
The amount of the adjusting entry to record the estimated uncollectible accounts receivables is $9,000
Answer: A way to earn money.
Explanation: There are many other ways to earn, like selling drugs, or robbing a elderly woman who tries to hit you with her cheap shoulder bag. There are many ways.
Answer:
The correct answer is A: interest= $21048
Explanation:
An amortization schedule is a complete table of periodic loan payments, showing the amount of principal and the amount of interest that comprise each payment until the loan is paid off at the end of its term. While each periodic payment is the same amount early in the schedule, the majority of each payment is interest; later in the schedule, the majority of each payment covers the loan's principal.
Each payment is the same ($49,148), but the proportions of interest and capital pay changes. The interest proportion decreases from pay to pay.
Loan= 186000
i= 15%
n= 6 years
First pay:
i=186000*0,15=27900
amortization= 49148-27900=21248
Second pay:
i=(186000-21248)*0,15=24712
amort=49148-24712=24436
Third pay:
i=(164752-24436)*0,15=21048
amort=49148-21048=28100
While payments progress, interest decreases and amortization increases.
