Step 1
<u>Find the value of s</u>
we know that
In a Rhombus all sides are congruent
so
![AB=BC=CD=DA](https://tex.z-dn.net/?f=AB%3DBC%3DCD%3DDA)
![AB=9s+29\\CD=10s-16](https://tex.z-dn.net/?f=AB%3D9s%2B29%5C%5CCD%3D10s-16)
equate AB and CD
![9s+29=10s-16\\](https://tex.z-dn.net/?f=9s%2B29%3D10s-16%5C%5C)
Combine like term
![10s-9s=29+16\\](https://tex.z-dn.net/?f=10s-9s%3D29%2B16%5C%5C)
![s=45\ units](https://tex.z-dn.net/?f=s%3D45%5C%20units)
<u>The answer Part a) is</u>
the value of s is ![45\ units](https://tex.z-dn.net/?f=45%5C%20units)
Step 2
<u>Find the value of side AB</u>
![AB=9s+29](https://tex.z-dn.net/?f=AB%3D9s%2B29)
substitute the value of s
![AB=9*45+29=434\ units](https://tex.z-dn.net/?f=AB%3D9%2A45%2B29%3D434%5C%20units)
Remember that the sides are congruent
![AB=BC=CD=DA](https://tex.z-dn.net/?f=AB%3DBC%3DCD%3DDA)
therefore
<u>the answer Part b) is</u>
The length of the side BC is ![434\ units](https://tex.z-dn.net/?f=434%5C%20units)
Answer:
thats not easy
Step-by-step explanation:
Answer:
(- 4, 9 )
Step-by-step explanation:
Given the 2 equations
3x + 4y = 24 → (1)
3x + 2y = 6 → (2)
Subtract (2) from (1) term by term to eliminate x
3x - 3x + (4y - 2y) = 24 - 6
2y = 18 ( divide both sides by 2 )
y = 9
Substitute y = 9 into either of the 2 equations and solve for x
Substituting into (1)
3x + 4(9) = 24
3x + 36 = 24 ( subtract 36 from both sides )
3x = - 12 ( divide both sides by 3 )
x = - 4
solution is (- 4, 9 )
Answer:
Step-by-step explanation:
Three digits
They add up to fifteen. (Example: 6 + 4 + 5 = 15.)
The Hundreds digit is 1 more than the units digit. (Example: 6 is 1 more than 5 in the example number.)
The Units digit is 1 more thn the tens digit. (Example: 5 is more then 4 in the example number.)
One digit in her number is 4.
Are YOU going to get candy?
Hope this helps :)