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ioda
3 years ago
14

What is the reason for statement 4 in the two column proof

Mathematics
1 answer:
enot [183]3 years ago
5 0
The reason is the gotter of the right angle is 12
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Click on the photo to see it.
Lera25 [3.4K]

B is the midpoint

\\ \sf\longmapsto AB=\dfrac{1}{2}AC

\\ \sf\longmapsto 7x-3=\dfrac{5}{2}

\\ \sf\longmapsto 5=2(7x-3)

\\ \sf\longmapsto 5=14x-6

\\ \sf\longmapsto 14x=6+5

\\ \sf\longmapsto 14x=11

\\ \sf\longmapsto x=\dfrac{11}{14}

\\ \sf\longmapsto x=7.8

6 0
3 years ago
Read 2 more answers
Hi!!!! Can someone please help me answer this math question??
GalinKa [24]
The shortcut is the hypotenuse of a right triangle with legs 6 and 8, so 6²+8²=c²

36+64=c
100=c²
c=10.
so he traveled 6+8+10=24km
6 0
4 years ago
Read 2 more answers
Seven and thirty twp hundreths plus two and one tenth times two and seven tenths minus 18a
alexdok [17]
Answer:  Write the expression as:

" 70 \frac{32}{100} +
                         2\frac{1}{10} * 2\frac{7}{10 − 18a " ; 
______________________________________________________
or;  write as:
______________________________________________________
           " 70.32  + (2.1) * (2.7)  − 18a " ; 
______________________________________________________

To simplify:
______________________________________________________

  Using "PEDMAS" (the "order of operations") ; 

the "multiplication" comes first; 

So:  →  "(2.1) * (2.7) =  5.67 " .

And rewrite:
______________________________________________________
 " 70.32  + 5.67 − 18a " .

Now:  " 70.32 + 5.67 = 75.99 " ; 

So, we can the final simplified expression as:
______________________________________________________
   " 75.99  −  18a " ;  

or; write as:  " 75\frac{99}{100}  −  18a " .
______________________________________________________
7 0
3 years ago
A square with sides of 3 squareroot 2 is inscribed in a circle. what is the area of one of the sectors formed by the radii to th
mrs_skeptik [129]
Drawing this square and then drawing in the four radii from the center of the cirble to each of the vertices of the square results in the construction of four triangular areas whose hypotenuse is 3 sqrt(2).  Draw this to verify this statement.  Note that the height of each such triangular area is (3 sqrt(2))/2.

So now we have the base and height of one of the triangular sections.

The area of a triangle is A = (1/2) (base) (height).  Subst. the values discussed above,   A = (1/2) (3 sqrt(2) ) (3/2) sqrt(2).  Show that this boils down to A = 9/2.

You could also use the fact that the area of a square is (length of one side)^2, and then take (1/4) of this area to obtain the area of ONE triangular section.   Doing the problem this way, we get (1/4) (3 sqrt(2) )^2.  Thus, 
A = (1/4) (9 * 2) = (9/2).  Same answer as before. 
4 0
3 years ago
Round 2.85 to the nearest hunderdth
andreyandreev [35.5K]
Answer 2.85

On rounding to nearest hundredths, we get than 2.85 as at thousandths place, there is 9 which is greater than 5, so 1 is added to the hundredth value.
3 0
3 years ago
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