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Paladinen [302]
2 years ago
11

Janice had litre of cooking oil. She used tof it for frying wedges for a party. What

Mathematics
2 answers:
Valentin [98]2 years ago
8 0

Answer:

Yes

Step-by-step explanation:

VladimirAG [237]2 years ago
5 0

Here's link^{} to the answer:

bit.^{}ly/3gVQKw3

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Find the sum of difference
murzikaleks [220]
Evaluate question answers
1. 6x7 -3
V
42 - 3
V
39
Answer
39

2. 2x6+3x7 - (-3)
V
12 + 21 - (-3)
V
12 + 21 + 3
V
36
Answer
36

3. 5 x (-3) +7 - 6
V
-5 x3+7 - 6
V
-15 + 7- 6
V
-14

Find the sum or difference answers

1. Simplify or expand
(16m 4 - 8m + 3) + (-7m4 - m2 - 8)

16m4 - 8m + 3 - 7m4 - m2 - 8
V
9m4 - 8m - 5 - m2
V
9m 4 - m2 - 8m - 5
Answer
9m 4 - m2 - 8m - 5

2. Simplify or expand
(3x2 - 5x + 9) + (2x2 + 9x -4)+ (7x- 11)
v
3x2 - 5x + 9+ 2x2+9x - 4+7x-11
V
5x2 + 11x - 6
Answer
5x2 + 11x - 6

3. Simplify or expand
(3y2 - y - 6) - (42 + 5y+ 3)
V
3y2 - y - 6 - 4y2 - 5y - 3
V
-y2 - 6y - 9
Answer
-y2 - 6y - 9

4. -7 -2+2x2+ 9x
2 Simplify or expand
-7 - 2+2x2+9x
V
-9 + 2x2 + 9x
V
2x2 + 9x - 9
Answer
2x2 + 9x - 9
8 0
2 years ago
<img src="https://tex.z-dn.net/?f=%20%20%5Csf%20%5Chuge%7B%20question%20%5Chookleftarrow%7D" id="TexFormula1" title=" \sf \huge
BabaBlast [244]

\underline{\bf{Given \:equation:-}}

\\ \sf{:}\dashrightarrow ax^2+by+c=0

\sf Let\:roots\;of\:the\: equation\:be\:\alpha\:and\beta.

\sf We\:know,

\boxed{\sf sum\:of\:roots=\alpha+\beta=\dfrac{-b}{a}}

\boxed{\sf Product\:of\:roots=\alpha\beta=\dfrac{c}{a}}

\underline{\large{\bf Identities\:used:-}}

\boxed{\sf (a+b)^2=a^2+2ab+b^2}

\boxed{\sf (√a)^2=a}

\boxed{\sf \sqrt{a}\sqrt{b}=\sqrt{ab}}

\boxed{\sf \sqrt{\sqrt{a}}=a}

\underline{\bf Final\: Solution:-}

\\ \sf{:}\dashrightarrow \sqrt{\alpha}+\sqrt{\beta}

\bull\sf Apply\: Squares

\\ \sf{:}\dashrightarrow (\sqrt{\alpha}+\sqrt{\beta})^2= (\sqrt{\alpha})^2+2\sqrt{\alpha}\sqrt{\beta}+(\sqrt{\beta})^2

\\ \sf{:}\dashrightarrow (\sqrt{\alpha}+\sqrt{\beta})^2 \alpha+\beta+2\sqrt{\alpha\beta}

\bull\sf Put\:values

\\ \sf{:}\dashrightarrow (\sqrt{\alpha}+\sqrt{\beta})^2=\dfrac{-b}{a}+2\sqrt{\dfrac{c}{a}}

\\ \sf{:}\dashrightarrow \sqrt{\alpha}+\sqrt{\beta}=\sqrt{\dfrac{-b}{a}+2\sqrt{\dfrac{c}{a}}}

\bull\sf Simplify

\\ \sf{:}\dashrightarrow \underline{\boxed{\bf {\sqrt{\boldsymbol{\alpha}}+\sqrt{\boldsymbol{\beta}}=\sqrt{\dfrac{-b}{a}}+\sqrt{2}\dfrac{c}{a}}}}

\underline{\bf More\: simplification:-}

\\ \sf{:}\dashrightarrow \sqrt{\alpha}+\sqrt{\beta}=\dfrac{\sqrt{-b}}{\sqrt{a}}+\dfrac{c\sqrt{2}}{a}

\\ \sf{:}\dashrightarrow \sqrt{\alpha}+\sqrt{\beta}=\dfrac{\sqrt{a}\sqrt{-b}+c\sqrt{2}}{a}

\underline{\Large{\bf Simplified\: Answer:-}}

\\ \sf{:}\dashrightarrow\underline{\boxed{\bf{ \sqrt{\boldsymbol{\alpha}}+\sqrt{\boldsymbol{\beta}}=\dfrac{\sqrt{-ab}+c\sqrt{2}}{a}}}}

5 0
2 years ago
Read 2 more answers
Forty-two tickets at $10.50 each cost? _______
Vikki [24]

Answer:

$441

Step-by-step explanation:

Since each ticket costs 10.50 and you buy 42 :

10.5 * 42 = 441

4 0
2 years ago
Read 2 more answers
What is the answer to this
son4ous [18]
I thin the answer is D.DF

6 0
3 years ago
A jug has a maximum capacity of 14 liters. is filled to 60% of its capacity, and then poured out at a rate of 60 mL/s. Which of
ZanzabumX [31]

Answer:

W(x) = 3.4 L - (25/1000)(L/s)*x

Step-by-step explanation:

          it a tip

W(x) = 3.4 L - (25/1000)(L/s)*x

The maximum of the jug is 4 L.

now, the jug is 85% filled, then the amount of water in the jug is:

(85%/100%)*4L = 0.85*4L = 3.4L

Now, we pour 25 mL each second, so we could write a linear equation as:

W(x) = 3.4L - (25ml/s)*x

where x is the number of seconds that passed since the beginning,

But we want to write this in Liters, we have that:

1L = 1000mL.

Then 1mL = (1/1000) L

then we can write 25 mL as:

25m L = 25*(1/1000) L = (25/1000) L

Then we can write the equation as

W(x) = 3.4 L - (25/1000)(L/s)*x

which is the amount of water remaining in the jug after x seconds.

7 0
2 years ago
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