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wlad13 [49]
2 years ago
13

Russell has been training for the Emerald Valley Race. The first week he trained, he ran 5 days and took the same two routes eac

h day. He ran 2 miles around the football field before school and ran a longer route through his neighborhood after school. By the end of the week, Russell had run a total of 30 miles.
Which equation can Russell use to find how many miles, x, he ran each day after school?
Mathematics
2 answers:
melamori03 [73]2 years ago
7 0

Answer:the equation would be something like 30=5x+10

Step-by-step explanation:we know the total is 30 miles

he ran 5 days

the morning run is 2 miles

2*5=10

10 plus the unknown miles times 5 days gives us 30

so 30=5x+10 subtract 10 both sides

20= 5x=20

divide both sides by 5

x=4

Goshia [24]2 years ago
4 0

Answer:

x=4

Step-by-step explanation:

5day, 2m before school, total 10m before school

5x after school

10+5x=30

5x=30-10

5x=20

x=4

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the sales price for a bicycle $315. the original price was first discounted by 5o% and then discounted by 10%. find the original
VMariaS [17]

Answer:

?× ( 1 − 50/ 100 ) × ( 1 − 10/ 100 ) = $ 315            ? = $ 315 /( .5 ) ( .9 ) = $ 700

Step-by-step explanation:

5 0
3 years ago
HURRRRRY <br> question is is pdf file below<br> which is the correct answer?
Mekhanik [1.2K]

Answer: 875

Step-by-step explanation:

5 0
1 year ago
Suppose that there are five young women and six young men on an island. Each woman is willing to marry some of the men on the is
pochemuha

Answer:

Based on the current information, the last man remaining unmarried will be a choice between two

Jason marries Anna

Matt marries Elizabeth

Kevin marries Barbara

Larry marries Diane

Carol can marry either Nick or Oscar

Step-by-step explanation:

The basic method to sort which woman will be marrying which man is simple.

We have to extract the choice by comparing choices of each woman side by side and then selecting the least common one and hence sorting one by one.

First, let's name all the women and men

1. Anna

2. Barbara

3. Carol

4. Diane

5. Elizabeth

We will refer to them with the initial letter of their name . A for Anna, B for Barbara, C for Carol, D for Diane, E for Elizabeth.

The men :

1. Jason

2. Larry

3. Matt

4. Kevin

5. Oscar

6. Nick

And they will be referred as J for Jason, L for Larry, M for Matt, K for Kevin, O for Oscar  and N for Nick.

Options for A : J , L ,M

Options for B : K, L

Options for C : J, N , O

Options for D : J, L , N , O

Options for E : J, M

As we can see , no one else wants Kevin other than Barbara so :

Kevin marries Barbara

Moving onwards:

Elizabeth can marry either Jason or Matt,

Meanwhile Anna can marry either Jason , Larry or Matt  

Hence,

Matt marries Eilzabeth

as Anna has two more choices still which are Jason and Larry.

Further, seeing the options for Carol and Diane

Carol can marry either Jason, Nick or Oscar while Diane can marry Larry as well as Jason , Nick and Oscar

We can select Jason as the match for Anna as Larry is also a choice for Diane.

Hence, Jason marries Anna

Now we are left with Larry , Nick and Oscar.

Since Carol can only decide from Nick and Oscar but Diane can decide from Larry, Nick and Oscar. Larry is the ideal option for Diane

so, Larry marries Diane

Now in the end, Carol can either choose between Nick or Oscar.

If she chooses Nick to marry, Oscar is left single

If she chooses Oscar to marry, Nick is left single.

7 0
3 years ago
Write your answer as a decimal or whole number.<br><br> ___% of $75=$42
Basile [38]

Answer:

x=56

Step-by-step explanation:

\frac{x}{100} · \frac{42}{75}

then cross multiply

4200=75x

x=56

3 0
3 years ago
In a certain country the life expectancy for women in 1990 was 45 and in 2000 it was 85?years. Assuming that life expectancy bet
Darya [45]

Answer:

49145 years

Step-by-step explanation:

In a certain country the life expectancy for women in 1990 was 45 and in 2000 it was 85?years.

Assuming that life expectancy between 2000 and 2100 increases by the same percentage as it did between 1900 and 2000,what will life expectancy be for women in 2100?

In 10 years, the expectancy increased by 85/45 = 17/9

between 2000 and 2100, it will increas by 10 time 10 years, so expected expectancy is  85*(\frac{85}{45})^{10} = 49145  years

4 0
3 years ago
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