Your question is already in decimal form :) but heres fraction!
let's find the area of the outer circle and the inside circle
the inside's circle area
A= π x 6²=36π
the outer's
A' = π x 4x²= 4πx²
A'-A=4πx²- 36π=160πcm² equivalent to x²- 9=40, so x²=49 implies x =sqrt(49)=7, x=7.
8/15 x 5/6
•multiply across the numerator and denominator.
= 40/90
• then find a common factor that will go into both the numerator and denominator equally.
Common factor: 5
= 8/18
•there is another common factor, which is 2
Simplified:
=4/9
Step-by-step explanation:
Simplify the left side:
5x - 20 = 3x + 4
Move all terms containing x to the left side of the equation:
2x - 20 = 4
Move all terms not containing x to the right side of the equation:
2x = 24
Divide each term by 2 and simplify:
x = 12
