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vekshin1
2 years ago
5

What’s another way to write the equation (40x4)-(32x4)=32

Mathematics
1 answer:
zysi [14]2 years ago
7 0

Answer:

160-128=32

Step-by-step explanation:

distribute what is in the parentheses

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-3b+7=13 solve for b
sleet_krkn [62]

Answer:

b =-2

Step-by-step explanation:

-3b+7=13

Subtract 7 from each side

-3b+7-7=13-7

-3b = 6

Divide each side by -3

-3b/-3 = 6/-3

b = -2

8 0
3 years ago
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2) ½ b – 39 = 101 please show your work
aliya0001 [1]
1/2 b-39=101
       +39  +39
1/2 b= 140
2(1/2) b= 140(2)
b=280
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This is worth 20 points. If you do both questions you get brainlest!
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5.78♡︎♡︎ and 2.4♡︎♡︎ it’s possible i may be wrong but i’m pretty sure i’m right!✨ ♡︎Brainliest please!♡︎ Good luck with your test or homework hope this helped♡︎♡︎
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2 years ago
Fiona finds 1 shell on her first day at the beach. every day that wek she finds twice as many shells as she did the day before.
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Ok, so on the first day she finds one, the second she finds two, the third four, the fourth eight, the fifth sixteen, the sixth thirty two, and the seventh sixty four. The answer is 64
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3 years ago
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The endpoints of a diameter of a circle are (6,2) and (−2,5) . What is the standard form of the equation of this circle?
Paul [167]

Answer:

The standard form of the given circle is

(x-2)^2+(y-\frac{7}{2})^2=73

Step-by-step explanation:

Given that the end points of a diameter of a circle are (6,2) and (-2,5);

Now to find the standard form of the equation of this circle:

The center is (h,k) of the circle is the midpoint of the given diameter

midpoint formula is M=(\frac{x_{1}+x_{2}}{2},\frac{y_{1}+y_{2}}{2})

Let (x_{1},y_{1}) and (x_{2},y_{2}) be the given points (6,2) and (-2,5) respectively.

M=(\frac{6-2}{2},\frac{2+5}{2})

M=(\frac{4}{2},\frac{7}{2})

M=(2,\frac{7}{2})

Therefore the center (h,k) is (2,\frac{7}{2})

now to find the radius:

The diameter is the distance between the given points (6,2) and (-2,5)

d=\sqrt{(x_{2}-x_{1})^2+(y_{2}-y_{1})^2}

=\sqrt{(-2-6)^2+(5-2)^2}

=\sqrt{(-8)^2+(3)^2}

=\sqrt{64+9}

=\sqrt{73}

Therefore the radius is \sqrt{73}

i.e., r=\sqrt{73}

Therefore the standard form of the circle is

(x-h)^2+(y-k)^2=r^2

Now substituting the center  and radiuswe get

(x-2)^2+(y-\frac{7}{2})^2=(\sqrt{73})^2

(x-2)^2+(y-\frac{7}{2})^2=73

Therefore the standard form of the given circle is

(x-2)^2+(y-\frac{7}{2})^2=73

5 0
3 years ago
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