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notsponge [240]

3 years ago

13

How many times greater is the volume of the sphere than the volume of cone #1? Round your answer to the neared tenth. Use 3.14 f

or pi. PLS HELP

1 answer:

Aliun [14]3 years ago

7 0

butter bts

the only explanation for this world

cuz i've got that superstar glow so eohohohwoow

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The area of a rectangle is 54 m2 , and the length of the rectangle is 3 m more than twice the width. find the dimensions of the

Elina [12.6K]

L = 3 + 2w

Find the width
Area = 54
l × w = 54
(3 + 2w) × w = 54
3w + 2w^2 = 54
2w^2 + 3w - 54 = 0
(2w - 9)(w + 6) = 0
w = 9/2 or w = -6 (width shouldn't be negative)
w = 9/2
w = 4.5 m

Find the length
l = 3 + 2w
l = 3 + 2(4.5)
l = 3 + 9
l = 12 m

The width is 4.5 m, the length is 12 m

6 0

4 years ago

Simplify (0.4) to the third power

svetoff [14.1K]

0.064 is 0.4 to the third power

7 0

3 years ago

Read 2 more answers

Find the mass of the triangle with vertices (1; 0; 0), (0; 2; 0), (0; 1; 1) if the density function is given by (x; y; z)

Luda [366]

Answer:

$=\frac{17}{3}$

Step-by-step explanation:

Density of a function is $\rho(x,y)=x^{2} +y^{2}$

I have drawn the right angle triangle for visualization

equation for the line passing through (1,0) and (0,4) is

$\frac{y}{4} =\frac{x-1}{-1}$

$y=4-4x$

= $\int_{0}^1\int_{0}^{4-4x} (x^{2}+y^{2})dydx$

= $\int_{0}^{1}(x^{2}+\frac{y^{3} }{3})dx$

= $\int_{0}^{1}(x^{2}(4-4x)+\frac{1}{3}(4-4x)^{3} )dx$

= $\int_{0}^{1}(\frac{-76}{3}x^{3} +68x^{2}-64x^{}+\frac{64}{3} )dx$

= $=(\frac{-76}{3} \frac{x^{4} }{4})+\frac{68}{3}x^{3}-32x^{2}+\frac{64}{3}x^{})$

$=\frac{17}{3}$

3 0

3 years ago

Use the confidence interval to find the margin of error and the sample mean (0.118,0.220)

malfutka [58]

Answer:

μ = 0.169

ME = 0.051

Step-by-step explanation:

The confidence interval is:

CI = μ ± ME

So the mean is the middle of the confidence interval, and the margin of error is half the difference.

μ = (0.118 + 0.220) / 2 = 0.169

ME = (0.220 − 0.118) / 2 = 0.051

5 0

4 years ago

DIA [1.3K]

Answer:

is there a figure for this question?

5 0

4 years ago