<h3>Given :</h3>
Seena’s mother is 4 times as old as Seena. After 5 years her mother will be 3 times as old as she will be then .Find their present ages.
<h3>Solution :</h3>
✧ <u>Let us assume</u> :
Seena's age be x
Her mother's age be 4x
✧ <u>After </u><u>5</u><u> years</u> :
Seena's age = x + 5
Her mother's age = 4x + 5
✧ <u>Ratio of age after </u><u>5</u><u> years</u> :
Seena's mother = 3
Seena's ratio = 1
Hence, the equation is :
By cross multiplying we get
Hence, the ages are
Seena's age = x = 10 yrs
Her mother's age = 4x = 4 × 10 = 40 years
∴ <u>Seena's age is 10 and her mother's is 40 respectively</u>
The perpendicular slope is undefined because the slope for the given line is zero. 1/0 has no meaning at least for this problem.
y = 5 would be parallel. Any number could be put in there even a transcendental.
y = pi. is parallel to y = - 8
x = 3 would be perpendicular to y=-8
The two lines would meet at (3,8)
3/5 x 15 is 9
I hope this is what you were asking
Answer:
Step-by-step explanation:
Given a sample M(t)
M(t) = 120 • ( 81 / 625)^t
When is the fraction of the mass decay to 3/5 of it's mass
Generally
M(t) = Mo•(k^t)
The original mass is 120
Mo = 120
So, we want to find time when it decay to 3/5 of it's original mas
M = 3/5 × 120
M = 72
Then,
M(t) = 120 • ( 81 / 625)^t
72 = 120 • ( 81 / 625)^t
72 / 120 = ( 81 / 625)^t
0.6 = ( 81 / 625)^t
Take natural logarithmic of both sides
In(0.6) = In(81/625)^t
In(0.6) = t•In(81/625)
t = In(0.6) / In(81/625)
t = In(0.6) / In(0.1296)
t = 0.25 monthly
t = ¼ monthly
Answer:
(4,-4)
Step-by-step explanation: