Question

Seena’s mother is 7 times as old as Seena. After 4 years

Answer 1

Given :

Seena’s mother is 4 times as old as Seena. After 5 years her mother will be 3 times as old as she will be then .Find their present ages.

Solution :

✧ Let us assume :

Seena's age be x

Her mother's age be 4x

✧ After 5 years :

Seena's age = x + 5

Her mother's age = 4x + 5

✧ Ratio of age after 5 years :

Seena's mother = 3

Seena's ratio = 1

Hence, the equation is :

$\looparrowright\frak{ \frac{4x + 5}{x + 5} = \frac{3}{1} }$

By cross multiplying we get

$\looparrowright \frak{3(x + 5) = 4x + 5}$

$\looparrowright \frak{3x + 15 = 4x + 5}$

$\looparrowright \frak{x = 10}$

Hence, the ages are

Seena's age = x = 10 yrs

Her mother's age = 4x = 4 × 10 = 40 years

∴ Seena's age is 10 and her mother's is 40 respectively