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sergey [27]
3 years ago
9

Seena’s mother is 7 times as old as Seena. After 4 years

Mathematics
1 answer:
VashaNatasha [74]3 years ago
7 0
<h3>Given :</h3>

Seena’s mother is 4 times as old as Seena. After 5 years her mother will be 3 times as old as she will be then .Find their present ages.

<h3>Solution :</h3>

✧ <u>Let us assume</u> :

Seena's age be x

Her mother's age be 4x

✧ <u>After </u><u>5</u><u> years</u> :

Seena's age = x + 5

Her mother's age = 4x + 5

✧ <u>Ratio of age after </u><u>5</u><u> years</u> :

Seena's mother = 3

Seena's ratio = 1

Hence, the equation is :

\looparrowright\frak{ \frac{4x + 5}{x + 5}   =  \frac{3}{1} }

By cross multiplying we get

\looparrowright \frak{3(x + 5) = 4x + 5}

\looparrowright \frak{3x + 15 = 4x + 5}

\looparrowright \frak{x = 10}

Hence, the ages are

Seena's age = x = 10 yrs

Her mother's age = 4x = 4 × 10 = 40 years

∴ <u>Seena's age is 10 and her mother's is 40 respectively</u>

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