There are 50 pages in a chapter. Claire read 17 pages of the chapter on Sunday.

Mathematics

1 answer:

nexus9112 [7]2 years ago

5 0

Answer:

She read 34% of the chapter

Step-by-step explanation:

You divide 17 by 50 and that gives you your answer

17/50=.34

move the decimal point 2 places to the right and the gives you your precent

.34=34%

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2/3 is what percent of 1/4?

saveliy_v [14]

So if we take 1/4 to be the 100%, what is 2/3 in percentage off of it then?

$\bf \begin{array}{ccll}
amount&\%\\
\text{\textemdash\textemdash\textemdash}&\text{\textemdash\textemdash\textemdash}\\
\frac{1}{4}&100\\\\
\frac{2}{3}&p
\end{array}\implies \cfrac{\frac{1}{4}}{\frac{2}{3}}=\cfrac{100}{p}\implies \cfrac{1}{4}\cdot \cfrac{3}{2}=\cfrac{100}{p}\implies \cfrac{3}{8}=\cfrac{100}{p}
\\\\\\
p=\cfrac{8\cdot 100}{3}\implies p=\cfrac{800}{3}\implies p=266\frac{2}{3}\implies p\approx 266.\overline{66}$

yes, is a large value, because 2/3 is indeed larger than 1/4, more than twice as large.

8 0

3 years ago

Melissa has a collection of different colored hair bows. Some of the hair bows are big, and some of the hair bows are small. The

Brilliant_brown [7]

Answer:

7/55 or 12.727272727273%

Step-by-step explanation:

7/55 or 12.727272727273%

7 big and pink

so 7/?

?= amount of bows

and them up and you get 55

7/55

4 0

2 years ago

The sides of a rhombus with angle of 60° are 6 inches. Find the area of the rhombus.

ehidna [41]

1. Check the drawing of the rhombus ABCD in the picture attached.

2. m(CDA)=60°, and AC and BD be the diagonals and let their intersection point be O.

3. The diagonals:
i) bisect the angles so m(ODC)=60°/2=30°

ii) are perpendicular to each other, so m(DOC)=90°

4. In a right triangle, the length of the side opposite to the 30° angle is half of the hypothenuse, so OC=3 in.

5. By the pythagorean theorem, $DO= \sqrt{ DC^{2}- OC^{2} }= \sqrt{ 6^{2}- 3^{2} }=\sqrt{ 36- 9 }=\sqrt{ 27 }= \sqrt{9*3}=$
$=\sqrt{9}* \sqrt{3} =3\sqrt{3} (in)$

6. The 4 triangles formed by the diagonal are congruent, so the area of the rhombus ABCD = 4 Area (triangle DOC)=4* $\frac{DO*OC}{2}=4 \frac{3 \sqrt{3} *3}{2}$ = $=2*9 \sqrt{3}=18 \sqrt{3}$ ( $in^{2}$ )