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2 years ago

72% of ______ days is 18 days.

Mathematics

1 answer:

maks197457 [2]2 years ago

4 0

Answer:

25 days

Step-by-step explanation:

lets the blank = x

Convert 72% to decimal: 0.72

0.72x = 18

x = 18/0.72

x = 25

-Chetan K

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FromTheMoon [43]

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Step-by-step explanation:

Slope=rise/run

In this case we rise up 4

And we run 2 to the left which makes it a negative

So in this case the slope is -4/2

Which can be simplified to -2

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3 years ago

Find the sum: -2.75+(-3.25)+5

dedylja [7]

The answer is -1. Hope this helps :)

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3 years ago

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RideAnS [48]

Answer:

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Step-by-step explanation:

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3 years ago

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Which is the coordinate of pointA? A(8,-6) <br>B(-6, 8) <br>C(6,-8) <br>D(-8,-6)

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Step-by-step explanation:

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2 years ago

A solution initially contains 200 bacteria. 1. Assuming the number y increases at a rate proportional to the number present, wri

GuDViN [60]

Answer:

1. $\frac{dy}{dt}=ky$

2.543.6

Step-by-step explanation:

We are given that

y(0)=200

Let y be the number of bacteria at any time

$\frac{dy}{dt}$ =Number of bacteria per unit time

$\frac{dy}{dt}\proportional y$

$\frac{dy}{dt}=ky$

Where k=Proportionality constant

2. $\frac{dy}{y}=kdt$ ,y'(0)=100

Integrating on both sides then, we get

$lny=kt+C$

We have y(0)=200

Substitute the values then , we get

$ln 200=k(0)+C$

$C=ln 200$

Substitute the value of C then we get

$ln y=kt+ln 200$

$ln y-ln200=kt$

$ln\frac{y}{200}=kt$

$\frac{y}{200}=e^{kt}$

$y=200e^{kt}$

Differentiate w.r.t

$y'=200ke^{kt}$

Substitute the given condition then, we get

$100=200ke^{0}=200 \;because \;e^0=1$

$k=\frac{100}{200}=\frac{1}{2}$

$y=200e^{\frac{t}{2}}$

Substitute t=2

Then, we get $y=200e^{\frac{2}{2}}=200e$

$y=200(2.718)=543.6=543.6$

e=2.718

Hence, the number of bacteria after 2 hours=543.6

4 0

3 years ago