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vladimir1956 [14]
3 years ago
15

Based on the information in the table, how much will Henry earn if he worked 7 hours?

Mathematics
1 answer:
777dan777 [17]3 years ago
4 0

Answer:

D.

Step-by-step explanation:

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Triangle ABC has angle measures as shown A x-5 B 3x+30 C 35 qhat is the value x
Vinvika [58]

Answer:

x=30\ degrees

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Step-by-step explanation:

we know that

The sum of interior angles in a triangle must be equal to 180 degrees

so

(x-5)+(3x+30)+(35)=180\°

solve for x

4x=180\°-60\°

4x=120\°

x=30\°

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THE ANSWER IS THE THIRD ONE
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3 years ago
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2. How many terms are there in the expression: 3a + 6
Aliun [14]

Answer: 2

Step-by-step explanation: That expression is a binomial in any case the terms in a polynomial are separated by a plus or minus sign (+,-) so you can determine the number of terms by counting how many number or variable are being separated (ex: 3a+a-1 would have 3 terms and be a trinomial)

8 0
3 years ago
In a home theater system, the probability that the video components need repair within 1 year is 0.02, the probability that the
earnstyle [38]

Answer:

(a) The probability that at least one of these components will need repair within 1 year is 0.0278.

(b) The probability that exactly one of these component will need repair within 1 year is 0.0277.

Step-by-step explanation:

Denote the events as follows:

<em>A</em> = video components need repair within 1 year

<em>B</em> = electronic components need repair within 1 year

<em>C</em> = audio components need repair within 1 year

The information provided is:

P (A) = 0.02

P (B) = 0.007

P (C) = 0.001

The events <em>A</em>, <em>B</em> and <em>C</em> are independent.

(a)

Compute the probability that at least one of these components will need repair within 1 year as follows:

P (At least 1 component needs repair)

= 1 - P (No component needs repair)

=1-P(A^{c}\cap B^{c}\cap C^{c})\\=1-[P(A^{c})\times P(B^{c})\times P(C^{c})]\\=1-[(1-0.02)\times (1-0.007)\times (1-0.001)]\\=1-0.97216686\\=0.02783314\\\approx 0.0278

Thus, the probability that at least one of these components will need repair within 1 year is 0.0278.

(b)

Compute the probability that exactly one of these component will need repair within 1 year as follows:

P (Exactly 1 component needs repair)

= P (A or B or C)

=P(A\cap B^{c}\cap C^{c})+P(A^{c}\cap B\cap C^{c})+P(A^{c}\cap B^{c}\cap C)\\=[0.02\times (1-0.007)\times (1-0.001)]+[(1-0.02)\times 0.007\times (1-0.001)]\\+[(1-0.02)\times (1-0.007)\times 0.001]\\=0.02766642\\\approx 0.0277

Thus, the probability that exactly one of these component will need repair within 1 year is 0.0277.

7 0
3 years ago
Giving out extra points please help
andreyandreev [35.5K]

Answer:

i dont want extra one i only want the though one

5 0
3 years ago
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