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ivanzaharov [21]
3 years ago
8

What is the area of a triangle with a base of 1.3cm and height of 0.5 cm?

Mathematics
2 answers:
sammy [17]3 years ago
6 0

Answer:

0.325 cm²

Step-by-step explanation:

A = \frac{1}{2}bh = \frac{1}{2}*1.3*0.5 = 0.325 cm²

solniwko [45]3 years ago
5 0

Answer:

0.325

Step-by-step explanation:

It is 1.3 times the height which is 0.5, so we do this equation

(1.3 x 0.5) / 2

answer is 0.325

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8X +6Y+4<br> Y=-3X+9<br> using substitution what numbers are the variables X and Y
Svetach [21]

Answer:

(5,6)

Step-by-step explanation:

8X +6Y=4

Y=-3X+9

Substitute the second equation into the first.  Every place you see y put -3x+9)

8x +6(-3x+9)=4

Distribute

8x-18x +54 = 4

Combine like terms

-10x +54 = 5

Subtract 54 from each side

-10x +54-54=4-54

-10x = -50

Divide by -10

-10x/-10 = -50/-10

x= 5

Now we need to find y

y = -3x+9

y = -3(5) +9

y = -15+9

y= 6

(5,6)

6 0
3 years ago
How to find the area?!
NNADVOKAT [17]
Times the sides and add them
3 0
3 years ago
Read 2 more answers
both brian and jermaine solve the problem. brian says the answer is $40,704. jermaine's answer is $4,604.
Studentka2010 [4]
Could you possibly be more specific?what math problem did they solve? i can help but just be a little more specific so i can answer your question
7 0
3 years ago
What is b in terms of a and c?
aev [14]

Answer:

b=\sqrt{c^2-a^2}

Step-by-step explanation:

The given relation is

c=\sqrt{a^2+b^2}

To make b the subject, we square both sides of the equation to get;

c^2=(\sqrt{a^2+b^2})^2

c^2=a^2+b^2

Isolate b on one side of the equation;

c^2-a^2=b^2

Or

b^2=c^2-a^2

We take the positive square root of both sides to get;

b=\sqrt{c^2-a^2}

6 0
3 years ago
Please help me I don’t understand what I’m supposed to do ! Unit 1 - Triangle Congruence
Luba_88 [7]

Answer:

i dont either

Step-by-step explanation:

6 0
3 years ago
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