This stem and leaf plot shows the scores for the Lincoln middle school boys’ basketball team for the 2004 season.

Mathematics

2 answers:

uranmaximum [27]3 years ago

5 0

Answer: 72

Go to the very bottom of the table, look at the stem of 7 and the leaf of 2 (largest leaf of the group). Combining the stem and leaf leads to 70+2 = 72

bonufazy [111]3 years ago

4 0

Answer:

The answer is 72 .

Step-by-step explanation:

A Stem and Leaf Plot is a table where you have two columns named 'stem' and 'leaf'.

In the stem column, the values are the first digit or digits of the number and the leaf column, you usually can find the last digit.

So in our plot, we can see that the first number is 42, then 45, then 49, then we move to the second row, which are, 53, 54,56 and so on.

Therefore the game with the most points will be 72.

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dexar [7]

Answer:

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Step-by-step explanation:

8 0

3 years ago

Express this to single logarithm

zzz [600]

Answer: $\log_{2}\left(\frac{q^2\sqrt{m}}{n^3}\right)$

We have something in the form log(x/y) where x = q^2*sqrt(m) and y = n^3. The log is base 2.

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Explanation:

It seems strange how the first two logs you wrote are base 2, but the third one is not. I'll assume that you meant to say it's also base 2. Because base 2 is fundamental to computing, logs of this nature are often referred to as binary logarithms.

I'm going to use these three log rules, which apply to any base.

log(A) + log(B) = log(A*B)
log(A) - log(B) = log(A/B)
B*log(A) = log(A^B)

From there, we can then say the following:

$\frac{1}{2}\log_{2}\left(m\right)-3\log_{2}\left(n\right)+2\log_{2}\left(q\right)\\\\\log_{2}\left(m^{1/2}\right)-\log_{2}\left(n^3\right)+\log_{2}\left(q^2\right) \ \text{ .... use log rule 3}\\\\\log_{2}\left(\sqrt{m}\right)+\log_{2}\left(q^2\right)-\log_{2}\left(n^3\right)\\\\\log_{2}\left(\sqrt{m}*q^2\right)-\log_{2}\left(n^3\right) \ \text{ .... use log rule 1}\\\\\log_{2}\left(\frac{q^2\sqrt{m}}{n^3}\right) \ \text{ .... use log rule 2}$