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alexandr1967 [171]

3 years ago

11

Based on the values given in the table, which triangle is a right triangle?

2 answers:

GarryVolchara [31]3 years ago

5 0

Answer: triangle F

Step-by-step explanation:

creativ13 [48]3 years ago

3 0

F, because it has a right angle! Hope this helps :)

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4m+2(m-5)=26<br> What USB the variable. Distribute first

NARA [144]

4m+2 (m-5)=26
4m+2m-10=26
6m-10=26
6m=36
M=6

3 0

3 years ago

Lissie set a goal to save $320 for a new computer. So far she has saved $112. What percent of her goal has Lissie saved so far?

Mariulka [41]

These are false. Tami will need to work 11 weeks to get to her goal. To find out this problem, first take out the 100 from the 320 which then gives you 220. Then divide 220 by 20 which gives you 11. 1 is wrong because Tami does not have to work more than 21 weeks to get to her goal. 2 is also wrong because Tami does not need to save more that 11 weeks to get to her goal, she has to work 11 weeks only.

7 0

3 years ago

What is 1/2" plus 5/8"

Burka [1]

The answer for 1/2 plus
5/8 is 6/10

6 0

3 years ago

Write the equation of the quadratic function that passes through the points (-1, 1), (1, 5), and (2,10).

Serjik [45]

Answer:

$\displaystyle f(x)=x^2+2x+2$

Step-by-step explanation:

<u>System Of Linear Equations </u>

In this problem, we'll need to solve a 3x3 system of linear equations because we have three unknowns and three conditions.

We are required to find the equation of the quadratic function that passes through the points (-1, 1), (1, 5), and (2,10)

The general quadratic function can be written as

$\displaystyle f(x)=ax^2+bx+c$

We need to find the values of a,b, and c. Let's use the first condition, i.e. f(-1)=1

$\displaystyle f(-1)=a(-1)^2+b(-1)+c$

$\displaystyle f(-1)=a-b+c$

$\displaystyle a-b+c=1.....[eq\ 1]$

Now we use the second condition f(1)=5

$\displaystyle f(1)=a(1)^2+b(1)+c$

$\displaystyle f(1)=a+b+c$

$\displaystyle a+b+c=5.......[eq\ 2]$

Finally, we use the third condition f(2)=10

$\displaystyle f(2)=a(2)^2+b(2)+c$

$\displaystyle f(2)=4a+2b+c$

$\displaystyle 4a+2b+c=10....[eq\ 3]$

We put together eq 1, eq 2, and eq 3 to form the system

$\displaystyle \left\{\begin{matrix}a-b+c=1\\ a+b+c=5\\ 4a+2b+c=10\end{matrix}\right.$

Adding the first two equations we have

$\displaystyle 2a+2c=6$

$\displaystyle a+c=3$

And also

$\displaystyle b=2$

Using the above equation and the value of b in the third equation, we have

$\displaystyle \left\{\begin{matrix}a+c=3\\ 4a+c=6\end{matrix}\right.$

Subtracting the first equation from the second

$\displaystyle 3a=3$

$\displaystyle a=1$

And therefore

$\displaystyle c=2$

Now we have all the values, the quadratic function is

$\displaystyle \boxed{f(x)=x^2+2x+2}$

6 0

3 years ago

Do the quotients always have the same number of digits when diving 3digit numbers by 1 digit numbers

ratelena [41]

Answer:

No.

example: 123 ÷ 3 = 41 (2 digits)

425 ÷ 5 = 85 (2 digits)

but, if 428 ÷ 2 = 214, which gives us 3 digits but not 2

∴, the quotient doesn't always have the no. of digits when we divide 3 digit no. s by 1 digit no. s.

5 0

3 years ago