Answer:
Dimensions of printed area
w = 8.95 cm
h = 13.44 cm
A(max) = 120.28 cm²
Step-by-step explanation:
Lets call " x " and "y" dimensions of the poster area ( wide and height respectively) . Then
A(t) = 180 cm² = x*y y = 180/ x
And the dimensions of printed area is
A(p) = ( x - 2 ) * ( y - 3 ) then as y = 180/x we make A function of x only so
A(x) = ( x - 2 ) * ( 180/x - 3 ) ⇒ A(x) = 180 - 3x - 360/x +6
A(x) = - 3x - 360 /x + 186
Taking derivatives on both sides of the equation we get:
A´(x) = -3 + 360/ x²
A´(x) = 0 -3 + 360/ x² = 0 -3x² + 360 = 0
x² = 120 ⇒ x = √120 x = 10.95 cm
And y = 180 / 10.95 ⇒ y = 16.44 cm
Then x and y are the dimensions of the poster then according to problem statement
w of printed area is x - 2 = 10.95 - 2 = 8.95 cm
and h of printed area is y - 3 = 16.44 - 3 = 13.44 cm
And the largest printed area is w * h = ( 8.95)*(13.44)
A(max) = 120.28 cm²
Answer:
False.
Step-by-step explanation:
The ratio is 1:500, which means that the model will be 500 times smaller than the real deal.
The real airplane is 50 metres, or 5,000 centimetres. The model is 50 cm. 5,000 / 50 = 1,000 / 10 = 100 / 1 = 100. Since 100 is NOT equal to 500, the answer is false.
Hope this helps!
Answer:
11
Step-by-step explanation:
Work backwards and reverse the operations to find the original number.
Reverse the operations for add four: 8 - 4 = 4
Reverse the operations for take the square root: 4² = 16
Reverse the operations for subtract six: 16 + 6 = 22
Reverse the operations for double the number: 22 ÷ 2 = 11
