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zmey [24]
3 years ago
8

Five times what number plus 10 equals 20?

Mathematics
2 answers:
Shkiper50 [21]3 years ago
7 0

Answer: 2

Step-by-step explanation: five times 2 is 10 plus 10 would equal 20

Readme [11.4K]3 years ago
3 0

Answer:

2

Step-by-step explanation:

5*2=10+10=20

hope this helps

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Find the value of x.
Sonja [21]

Answer:

4. x=10

5. x=15

6. x=20

7. x=4

Step-by-step explanation:

4. 50+4x=90

90-50=40

40/4=10

x=10

5. (2x+60)+6x=180

6x+2x=8x

8x+60=180

180-60=120

8x=120

120/8=15

x=15

6. 3x+30=90

90-30=60

60/3=20

x=20

7. (8x+120)+7x=180

8x+7x=15x

15x+120=180

180-120=60

15x=60

60/15=4

x=4

4 0
3 years ago
Juarez scored 32 points in a basketball game. He scored twice as many baskets worth 3 points than baskets worth 2 points. How ma
Ksju [112]

Answer:

8 baskets worth 3 points each and 4 baskets worth 2 points each

Step-by-step explanation:

It is 8 baskets worth 3 points each and 4 baskets worth 2 points each because it says Juarez scored twice as many baskets worth 3 points than the baskets worth 2 points. 4 x 2 = 8

-----------------------------------------------------------------------------

6 baskets worth 3 points each and 7 baskets worth 2 points each : wrong because 7 x 2 = 14.

10 baskets worth 3 points each and 1 basket worth 2 points : wrong because 1 x 2 = 2.

4 baskets worth 3 points each and 10 baskets worth 2 points each: wrong because 10 x 2 = 40.

3 0
4 years ago
Read 2 more answers
What is the value of b - c if a = 18, b= 27, and c= 11? <br>O 16<br>O 11 <br>0 9<br>0 29​
pentagon [3]

Answer: 16

Step-by-step explanation: 27-11=16

4 0
3 years ago
Read 2 more answers
What are the missing parts that correctly complete the proof
bonufazy [111]

Answer:

2. \overline{AX}\cong \overline{BX}

3. PX \perp AB - definition of perpendicular

4. \angle PXA \cong \angle PXB - all right angles are congruent

6. \triangle AXP\cong \triangle BXP

7. \overline{PA} \cong \overline{PB}

Step-by-step explanation:

<u>Given: </u>Point P is the perpendicular bisector of AB

<u>Prove: </u>P is equidistant from the endpoints AB

<u>Proof.</u>

1. Point P is on the perpendicular bisector of AB - given

2.\overline{AX}\cong \overline{BX} - definition of bisector

3. PX \perp AB - definition of perpendicular

4.  \angle PXA \cong \angle PXB - all right angles are congruent

5. \overline{PX} \cong \overline{PX} - reflexive property of congruence

6. \triangle AXP\cong \triangle BXP - SAS congruency postulate

7. \overline{PA} \cong \overline{PB} - corresponding parts of congruent triangles are congruent

8. Point P is equidistant from the endpoints of AB - definition of equidistant

5 0
3 years ago
<img src="https://tex.z-dn.net/?f=%5Cfrac%7Bp%7D%7B5%7D" id="TexFormula1" title="\frac{p}{5}" alt="\frac{p}{5}" align="absmiddle
tatyana61 [14]

Answer:

p ≥ -10

Step-by-step explanation:

first, subtract one from each side to get:

p/5 ≥ -2

lastly, multiply each side by 5

p ≥ -10

6 0
3 years ago
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