Answer:
![2(a^3+b^2+11)+1(3+a^3+b+11)=3a^3+2b^2+b+36](https://tex.z-dn.net/?f=2%28a%5E3%2Bb%5E2%2B11%29%2B1%283%2Ba%5E3%2Bb%2B11%29%3D3a%5E3%2B2b%5E2%2Bb%2B36)
Step-by-step explanation:
I assume that you need simplification of the given expression.
The given expression is:
![2(a^3+b^2+11)+1(3+a^3+b+11)](https://tex.z-dn.net/?f=2%28a%5E3%2Bb%5E2%2B11%29%2B1%283%2Ba%5E3%2Bb%2B11%29)
Using distributive property and multiplying 2 inside the parenthesis and 1 inside the other parenthesis. This gives,
![2(a^3+b^2+11)=2\times a^3+2\times b^2+2\times 11\\2(a^3+b^2+11)=2a^3+2b^2+22\\\\1(3+a^3+b+11)=1\times 3+1\times a^3+1\times b+1\times 11\\1(3+a^3+b+11)=3+a^3+b+11=a^3+b+14](https://tex.z-dn.net/?f=2%28a%5E3%2Bb%5E2%2B11%29%3D2%5Ctimes%20a%5E3%2B2%5Ctimes%20b%5E2%2B2%5Ctimes%2011%5C%5C2%28a%5E3%2Bb%5E2%2B11%29%3D2a%5E3%2B2b%5E2%2B22%5C%5C%5C%5C1%283%2Ba%5E3%2Bb%2B11%29%3D1%5Ctimes%203%2B1%5Ctimes%20a%5E3%2B1%5Ctimes%20b%2B1%5Ctimes%2011%5C%5C1%283%2Ba%5E3%2Bb%2B11%29%3D3%2Ba%5E3%2Bb%2B11%3Da%5E3%2Bb%2B14)
Therefore,
is equal to:
![2a^3+2b^2+22+a^3+b+14](https://tex.z-dn.net/?f=2a%5E3%2B2b%5E2%2B22%2Ba%5E3%2Bb%2B14)
Now, combining like terms using the commutative property of addition, we get:
![=(2a^3+a^3)+2b^2+b+(22+14)\\=3a^3+2b^2+b+36](https://tex.z-dn.net/?f=%3D%282a%5E3%2Ba%5E3%29%2B2b%5E2%2Bb%2B%2822%2B14%29%5C%5C%3D3a%5E3%2B2b%5E2%2Bb%2B36)
Therefore, the simplified form is ![3a^3+2b^2+b+36](https://tex.z-dn.net/?f=3a%5E3%2B2b%5E2%2Bb%2B36)
Just do 198 divide by 33. The answer is how much gas will be used.
Answer:
i think the answer is A
Step-by-step explanation:
Because it says four times and 4 times 4 =16
sorry tried my best(don't write this part down)lol
61+58=119
180-119=61=angle 2
180-61=119=angle 4
Solution :
Given data :
The mean length of the steel rod = 29 centimeter (cm)
The standard deviation of a normally distributed lengths of rods = 0.07 centimeter (cm)
a). We are required to find the proportion of rod that have a length of less than 28.9 centimeter (cm).
Therefore, P(x < 28.9) = P(z < (28.9-29) / 0.07)
= P(z < -1.42)
= 0.0778
b). Any rods which is shorter than
cm or longer than
cm that re discarded.
Therefore,
P (x < 24.84 or 25.16 < x) = P( -59.42 < z or -54.85)
= 1.052